Why is P/A equal to 83kPA at an eccentricity ratio of 1?

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Homework Statement


in this question , ( in second photo) i don't understand that why at eccentricity ratio = 1 , P/ A is 83kPA , why the vertical line is drawn at a point between 100 and 150 KL/r to find P/A ?

Homework Equations

The Attempt at a Solution


Is it wrong ? Or I left out something? [/B]
 
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The vertical line is drawn at the given kl/r of 104.
You are trying to cram 4 years of engineering into 4 weeks. It won't work. Focus on the basics please.
 
H
PhanthomJay said:
The vertical line is drawn at the given kl/r of 104.
You are trying to cram 4 years of engineering into 4 weeks. It won't work. Focus on the basics please.
How do we know that kl /r =104??