Why is Pure Water Most Soluble for AgCl?

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SUMMARY

The solubility of silver chloride (AgCl) is highest in pure water compared to other solutions such as 0.181 M HCl, 0.0176 M NH3, 0.744 M LiNO3, and 0.181 M NaCl. The Ksp expression for AgCl dissolution, Ksp = [Ag+][Cl-], indicates that the presence of competing ions in other solutions reduces the solubility of AgCl. Therefore, pure water, lacking additional ions, allows for maximum solubility of AgCl. This conclusion is supported by the fundamental principles of solubility product constants.

PREREQUISITES
  • Understanding of solubility product constants (Ksp)
  • Knowledge of ionic compounds and their dissociation in solutions
  • Familiarity with the concept of ion competition in solubility
  • Basic chemistry principles regarding solutions and solubility
NEXT STEPS
  • Research the solubility product constant (Ksp) of silver chloride (AgCl)
  • Learn about the effects of common ions on solubility
  • Explore the role of ammonia in solubility and complex ion formation
  • Investigate the solubility of other ionic compounds in pure water versus ionic solutions
USEFUL FOR

Chemistry students, educators, and anyone studying solubility principles and the behavior of ionic compounds in various solutions.

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Homework Statement


In which one of the following solutions is silver chloride the most soluble?

A) 0.181 M HCl B) 0.0176 M NH3 C) 0.744 M LiNO3 D) pure water E) 0.181 M NaCl

Homework Equations


the Ksp expression for the dissolution of AgCl is:

Ksp = [Ag+][Cl-]

The Attempt at a Solution



Could anyone please explain why the answer pure water is correct versus the other answers?

I have no idea why that is the answer.

Thanks in advance.
 
Physics news on Phys.org
Well --- I suspect you've picked up an errant text --- it's really supposed to be the ammonia solution.
 

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