Why is the a=dv/dt equation used in integration and when is it applicable?

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Discussion Overview

The discussion centers around the equation a = dv/dt, exploring its implications in integration and the conditions under which it is applicable. Participants examine the mathematical interpretation of derivatives and the use of differential forms in the context of integration techniques.

Discussion Character

  • Technical explanation
  • Mathematical reasoning
  • Debate/contested

Main Points Raised

  • One participant questions the interpretation of dv/dt as a derivative rather than a ratio, seeking clarification on its meaning.
  • Another participant asserts that dv/dt is indeed a mathematical formula for the derivative of v with respect to t, emphasizing its role in showing relationships between dependent and independent variables.
  • A later reply discusses the use of the equation dv = a dt in integration, particularly in the context of variable substitution, suggesting that it can be reformulated under certain conditions.
  • One participant expresses skepticism about the validity of treating adt as equal to dv, labeling it as notational "garnish" or "garbage" and implying that this may lead to confusion regarding limits of integration.

Areas of Agreement / Disagreement

Participants express differing views on the interpretation and application of the equation a = dv/dt, with no consensus reached on the validity of treating adt as equivalent to dv in integration.

Contextual Notes

There are unresolved questions regarding the assumptions underlying the use of differential forms and the implications of variable substitution in integration. Participants have not fully addressed the limitations of their interpretations.

vijay_singh
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I see in many text that a = dv/dt implies that

dv = a dt

How is that possible, can anybody please explain me. As far as i know dv/dt is a symbol for derivative of v w.r.t t and not ratio between dv and dt.
 
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What you wrote is in differential form.
 
dv/dt is not a symbol. It is the mathematical formula for the derivative of v with respect to t. This is how one would show any derivative of a dependent variable with respect to an independent variable.
 
bucher said:
dv/dt is not a symbol. It is the mathematical formula for the derivative of v with respect to t. This is how one would show any derivative of a dependent variable with respect to an independent variable.

And what did I say :-)
 
Now, WHY can we utilize at times the dv=adt formula, in particular, WHERE is it usable?

Answer:

When doing integration with the technique called substitution of variables (i.e the "inverse" of the chain rule):

Given a=dv/dt, we have, trivially:
\int_{t_{1}}^{t_{2}}adt=\int_{t_{1}}^{t_{2}}\frac{dv}{dt}dt
But the right-hand side can, by the theorem of substitution of variables, be reformulated, giving the identity:
\int_{t_{1}}^{t_{2}}adt=\int_{v(t_{1})}^{v(t_{2})}dv=\int_{v_{1}}^{v_{2}}dv

Now, by IGNORING that the limits of integration actually refers to the limits of DIFFERENT variables, we "may say" that the "integrands" are equal, i.e, adt=dv!


Thus, adt=dv should, at this stage of your education, be regarded as notational garnish (or garbage, if you like!)
 

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