Why is the acceleration on a point on a wheel what it is.

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SUMMARY

The acceleration of a point on the edge of a wheel, when the center is traveling at velocity V0, is calculated using the formula V0²/r, where r represents the radius of the wheel. This relationship is derived from the principles of centripetal acceleration, which is essential for understanding the motion of rolling objects. The angular velocity of the wheel plays a crucial role in determining this acceleration, as it relates linear velocity to the radius of the wheel.

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  • Centripetal acceleration principles
  • Understanding of angular velocity
  • Basic kinematics
  • Knowledge of rolling motion dynamics
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  • Study the relationship between linear velocity and angular velocity in rolling objects
  • Explore the derivation of centripetal acceleration formulas
  • Learn about the effects of radius on acceleration in circular motion
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Physics students, mechanical engineers, and anyone interested in the dynamics of rolling motion and circular acceleration.

Chronothread
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Hello. My brain doesn't seem to be working at the moment. If a wheel's center is traveling at V0, why is the acceleration of a point on the edge of the wheel equal to V02/r where r is the radius of the wheel? Thanks for your time.

Edit:

Oops should have have put a question mark in the title... meh.
 
Last edited:
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Chronothread said:
If a wheel's center is traveling at V0, why is the acceleration of a point on the edge of the wheel equal to V02/r where r is the radius of the wheel?.

Hi Chronothread! :smile:

(you didn't say :rolleyes: , but i assume the wheel is rolling, along a flat surface :wink:)

Use centripetal acceleration …

Hint: what is the angular velocity of the wheel?
 

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