Why is the atomic radius of Boron smaller than that of Be?

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Discussion Overview

The discussion centers on the atomic radius of Boron (B) compared to Beryllium (Be), exploring the reasons behind the observed size difference despite Boron having an additional p orbital. The scope includes theoretical considerations of electron configurations, ionization energies, and shielding effects.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant notes that the first ionization energy decreases from Be to B, suggesting that the outermost electron in B is held more loosely, yet this does not correlate with an expected increase in atomic radius.
  • Another participant proposes that the atomic radius of B is smaller due to a higher nuclear charge, despite its additional p orbital.
  • A participant expresses confusion about the initial question, reiterating the inquiry regarding the smaller atomic radius of B despite having an extra p orbital shielded by full 1s and 2s orbitals.
  • It is mentioned that the radius of the B+ ion is smaller than that of neutral Be, attributing this to the higher nuclear charge in B.
  • One participant raises a point about the non-spherical nature of p orbitals, questioning how the size of Boron is defined in terms of dimensions.

Areas of Agreement / Disagreement

Participants express differing views on the factors influencing the atomic radius of Boron compared to Beryllium, indicating that the discussion remains unresolved with multiple competing explanations.

Contextual Notes

There are limitations in the assumptions made regarding electron shielding and the influence of nuclear charge on atomic size, which are not fully explored or agreed upon.

mahela007
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The 1st ionization energy decreases from Be to B. This would suggest that the outermost electron is held more loosely in B. Also, considering the electron configurations of Be (1s2 2s2) and B (1s2 2s2 2p1) one would think that in B, the shielding effect of the 2s electrons on the p electron would also act to increase the atomic radius...
but alas :wink: that isn't how it is... Now.. the universal question: WHY?
 
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Because the configuration (1s2 2s2) in B is smaller in size due to higher nucleus charge, no?
 
Last edited:
Wait.. i think I made a mistake in my initial post.
What I meant to ask was why is the atomic radius of B smaller when it has an extra P orbital which is also shielded by full 1s and 2s orbitals?
 
mahela007 said:
Wait.. i think I made a mistake in my initial post.
What I meant to ask was why is the atomic radius of B smaller when it has an extra P orbital which is also shielded by full 1s and 2s orbitals?

Ion B+ radius is smaller than that of neutral Be despite the same electron configuration 1s2 2s2 just because the charge of nucleus in B is higher. The rest is a collective electronic effect, I think.

Besides, a p-state is not spherical. Which axe (dimension) is considered as the B-size?
 
Last edited:

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