Why is the Author Using Negative Signs in this Circuit Analysis Problem?

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Discussion Overview

The discussion revolves around the use of negative signs in circuit analysis, particularly regarding the direction of current flow in diagrams. Participants explore the implications of current direction as indicated by arrows in circuit diagrams and how these relate to calculated values.

Discussion Character

  • Technical explanation
  • Debate/contested
  • Conceptual clarification

Main Points Raised

  • Some participants question why negative signs are used in the context of current flow, particularly when different diagrams show conflicting signs for the same current direction.
  • It is noted that a negative sign indicates that the actual current flows in the opposite direction to that indicated by the arrows in the diagram.
  • One participant points out that the direction of IL is defined as down in the diagram, but the calculated current flows up, leading to a negative value.
  • Another participant highlights that while the direction of current in both diagrams appears downward, the signs differ due to the actual flow of currents being different as per the diagram definitions.
  • There is a suggestion that the choice of current direction can be arbitrary, and if the assumption is incorrect, the resulting negative sign in calculations reflects this error.
  • Participants express confusion regarding current flow and seek additional resources for clarification.

Areas of Agreement / Disagreement

Participants express varying interpretations of the use of negative signs in circuit analysis, indicating that multiple competing views remain. There is no consensus on the reasons behind the differing signs in the diagrams.

Contextual Notes

Some participants mention that the confusion may stem from habitual assumptions about current flow in circuits, and there are references to specific diagrams that are not visible in the discussion.

Who May Find This Useful

This discussion may be useful for students and individuals seeking to understand the principles of current flow in circuit analysis and the implications of directional signs in diagrams.

otomanb
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why the author is using negative sign there?

r27omo.jpg


And here the problem is different the author is using different current flow signs and one answer is positive and other is negative why is this so?

See this?
http://i42.tinypic.com/2rqdj5w.jpg
 
Last edited:
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Means that the current calculated points in the opposite direction to the arrow drawn on the diagram. Look at the current source - which direction is the current going to flow?
 
Because the direction of IL is defined in the diagram to be down, and the solution finds that the actual current is flowing up. So you indicate that with IL = -0.25mA.

EDIT -- Beaten out by Simon! :smile:
 
please see the second pic and reply please! it is contrary with the ist picture!
 
otomanb said:
please see the second pic and reply please! it is contrary with the ist picture!

Same reason. Look at how the arrows are defined for those two currents, and look at how the actual current flows.
 
direction of current in both pics is downward but in one pic there is negative sign and in other there is positive ?
 
otomanb said:
direction of current in both pics is downward but in one pic there is negative sign and in other there is positive ?

Look more closely in the 2nd pic. I1 is up and I2 is down as drawn on the figure.
 
understanding that.
sir do you have any book or video that will clear my concept about current flow ? because it's very puzzling to me!
 
  • #10
To me this is one of the beauties of the physics - you can draw the arrows on your circuits how you like and if you get it wrong, the math gives you a negative sign.

I think there are two sources of confusion here;
1. people get used to currents flowing clockwise around circuits so they end up going top-to-bottom through resistors - just turn the page around.
2. the minus sign was just inserted apropos of nothing in the working ... probably from considering the current source to be negative. If the circuit was a single loop, the reason for the choice would have been trivially obvious. Of course it would also work if you actually compute the equivalent circuit, considering "up" to be positive for current sources.
 
  • #11
In the second diagram we can assume any direction of load current, and if the load comes positive than the assumed direction is correct otherwise it is opposite.
 

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