Why Is the Exerted Force Equal and Opposite to the Electrostatic Force?

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Discussion Overview

The discussion revolves around the relationship between the force exerted on a charge in an electric field and the electrostatic force acting on that charge. Participants explore the implications of this relationship when displacing a charge slowly within a uniform electric field, addressing concepts of motion, force application, and work done.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • One participant questions why the force exerted on the charge must be equal and opposite to the electrostatic force, suggesting that a greater force would be necessary for movement.
  • Another participant clarifies that a net force of zero allows for constant velocity, indicating that a small force above the electrostatic force is sufficient to initiate motion.
  • A different viewpoint suggests that while a different force is needed to start motion, maintaining constant speed requires a force equal to the electrostatic force.
  • One participant emphasizes the significance of the term "very slowly," proposing that the force should be described as "infinitesimally greater than" the electrostatic force to allow for gradual acceleration and deceleration.

Areas of Agreement / Disagreement

Participants express differing views on the nature of the force required to move the charge, with some asserting that it must be greater than the electrostatic force to initiate movement, while others argue that an infinitesimal adjustment is sufficient. The discussion remains unresolved regarding the precise nature of the force application.

Contextual Notes

Participants note limitations such as friction, air resistance, and experimental accuracy that may affect the application of forces in practice.

ewr
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Hi, I found this on http://farside.ph.utexas.edu/teaching/302l/lectures/node32.html

"Consider a charge
img221.png
placed in a uniform electric field
img242.png
(e.g., the field between two oppositely charged, parallel conducting plates). Suppose that we very slowly displace the charge by a vector displacement
img50.png
in a straight-line. How much work must we perform in order to achieve this? Well, the force
img159.png
we must exert on the charge is equal and opposite to the electrostatic force
img359.png
experienced by the charge (i.e., we must overcome the electrostatic force on the charge before we are free to move it around). The amount of work
img124.png
we would perform in displacing the charge is simply the product of the force we exert, and the displacement of the charge in the direction of this force."

My question is why is the force we must exert on the charge is equal and opposite to the electrostatic force qE? Shouldn't the force be greater than qE? If it is equal and opposite than the charge won't move wouldn't it?

Thank you.
 
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This is a common misconception. If the force sum is zero, the charge moves at constant velocity.

The key point is that you just need a miniscule force above the electric one to start the motion. The key word is "slowly".
 
Yes and no. You need to apply a different force to start it moving (or change its motion in general). But if the charge is already moving you will have to apply a force qE to keep it moving at constant speed, is all he is saying. The work done by that force goes into the electric field (you are moving a charge and therefore changing the electric field).

Edit: beaten to it by Orodruin.
 
The key is the words 'very slowly'. Strictly speaking they should also replace their 'equal to' by 'infinitesimally greater than'.

The idea is that if F is infinitesimally larger than the electrostatic force for half the time and infinitesimally less than it for the other half, the particle will accelerate very slowly to a very slow maximum velocity in the desired direction, and then decelerate very slowly, to finally come to rest at the destination. Subject to limitations like friction, air resistance and experimental accuracy, we can make this infinitesimal difference as small as we like.

Edit: Haha, beaten to it by Orodruin and Ibix.
 

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