Why is the final potential of spring (Usf) equal to zero in problem b?

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The final potential energy of the spring (Usf) is equal to zero in problem b because the object is no longer in contact with the spring when it reaches the bottom of the incline. Since the spring is not being compressed or stretched at that point, there is no energy stored in it. The logic behind this conclusion is based on the relationship between potential energy and the displacement of the spring. Understanding this concept clarifies why Usf is zero in this scenario. The discussion highlights the importance of analyzing the conditions of the problem carefully.
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I'm having promblem with b. I checked the solution, but I did'nt understand the logic.

Kf+Ugf+Usf = Ki+Ugi+Usi

Usf= 0, Ki=0, Ugf= 0

I understand the logic's why they are equal to 0.

I don't understand why final potential of spring (Usf) is equal to zero?

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Now, I got it. I read the problem in detail.
 
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The potential energy that is stored in a spring depends on how far something is compressing or stretching the spring. So in b, when the object is at the bottom of the incline, it is no longer in contact with the spring, meaning it cannot be compressing the spring. since it is not compressing the spring that means there is no energy stored in it.
 
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Joseph Martinez said:
The potential energy that is stored in a spring depends on how far something is compressing or stretching the spring. So in b, when the object is at the bottom of the incline, it is no longer in contact with the spring, meaning it cannot be compressing the spring. since it is not compressing the spring that means there is no energy stored in it.

Thank you so much, I see it after posting thread.
 
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