Why is the graviton non-renormalizable?

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SUMMARY

The graviton is non-renormalizable due to the increasing number of counterterms required in the Lagrangian with each order of the perturbation expansion. Renormalization allows for the application of "weights" to Feynman diagrams, but this method fails for gravitons. The discussion references introductory papers on renormalization, specifically arXiv:0812.3578 and arXiv:hep-th/0212049, which provide foundational insights into the complexities of quantizing gravity.

PREREQUISITES
  • Understanding of relativistic electromagnetism (E&M)
  • Basic knowledge of quantum mechanics
  • Familiarity with Feynman diagrams
  • Concept of Lagrangian in quantum field theory
NEXT STEPS
  • Study the implications of non-renormalizability in quantum gravity
  • Explore advanced topics in perturbation theory
  • Read arXiv:0812.3578 and arXiv:hep-th/0212049 for deeper insights into renormalization
  • Investigate alternative approaches to quantizing gravity, such as string theory
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The discussion is beneficial for theoretical physicists, graduate students in physics, and researchers interested in quantum gravity and the challenges of renormalization.

cuallito
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Okay, I've taken relativistic E&M and the first semester of quantum mech.

Why is the graviton non-renormalizable? As I understand it, renormalization means that you can apply a "weight" to the feynman diagrams of an interaction to make it come out right (is that correct?) Why can you not do this for gravitons?
 
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cuallito said:
Okay, I've taken relativistic E&M and the first semester of quantum mech.

Why is the graviton non-renormalizable? As I understand it, renormalization means that you can apply a "weight" to the feynman diagrams of an interaction to make it come out right (is that correct?) Why can you not do this for gravitons?

Here are a couple of introductory papers on renormalisation:
http://arxiv.org/abs/0812.3578"

and

http://arxiv.org/abs/hep-th/0212049"

Part of the renormalization procedure involves adding counterterms to the Lagrangian. The problem with the conventional approach to quantizing gravity, as I understand it, is that the number of counterterms required grows with each order of the perturbation expansion.
 
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