Why is the new format necessary before differentiating?

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SUMMARY

The discussion centers on the necessity of reformulating the function B(t) before differentiation. The original attempt, B(t) = P(t)(1.05)^(20-t) ln(1.05), is incorrect due to improper application of differentiation rules. The correct approach involves rewriting B(t) by separating the components and applying the quotient rule effectively. This transformation is essential to simplify the differentiation process and avoid complications arising from negative exponents and multiple exponents.

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Homework Statement


http://postimage.org/]Screen_Shot_2015_10_27_at_9_16_09_PM.png[/PLAIN]
click image upload


Homework Equations


http://postimage.org/]Screen_Shot_2015_10_27_at_9_19_32_PM.png[/PLAIN]
free image upload


The Attempt at a Solution


So I wanted to differentiate B(t) by saying

B(t) = P(t)(1.05)20-t ln(1.05)

Apparently this is the wrong answer.

I'm supposed to change my function B(t) into this new form. From there I understand how they differentiated using the quotient rule. I can even understand how they got the new B(t) formula by splitting (1.05)20 from (1.05)-t, then changing that to 1/(1.05)t and multiplying by P(t).
http://postimage.org/]Screen_Shot_2015_10_27_at_9_58_05_PM.png[/PLAIN]
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What I don't understand is why my original attempt is wrong. Why is the new format necessary before we differentiate? It is because I have a negative exponent? Is it because I have two exponents?

Thanks for the help
 
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PhysicsBoyMan said:

Homework Statement


Screen_Shot_2015_10_27_at_9_16_09_PM.png[/PLAIN]
click image upload


Homework Equations


Screen_Shot_2015_10_27_at_9_19_32_PM.png[/PLAIN]
free image upload


The Attempt at a Solution


So I wanted to differentiate B(t) by saying

B(t) = P(t)(1.05)20-t ln(1.05)

Apparently this is the wrong answer.
B(t) is defined as a product, but it doesn't seem that you used the product rule.
PhysicsBoyMan said:
I'm supposed to change my function B(t) into this new form. From there I understand how they differentiated using the quotient rule. I can even understand how they got the new B(t) formula by splitting (1.05)20 from (1.05)-t, then changing that to 1/(1.05)t and multiplying by P(t).
Screen_Shot_2015_10_27_at_9_58_05_PM.png[/PLAIN]
image hosting sites


What I don't understand is why my original attempt is wrong. Why is the new format necessary before we differentiate? It is because I have a negative exponent? Is it because I have two exponents?

Thanks for the help
 
Last edited by a moderator:
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