Why is the partial derivative of Lx with respect to x zero

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M. next
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Why is it that partial derivative of Lx wrt x is zero?
where: Lx (Angular momentum along x)

Yes and for further info. they wrote beside this that dLx/dx =d(yPz - zPy)/dx = 0

I guess it resulted from some determinant but I just could not figure it out.

(This was a snatch of a problem in Poisson's Bracket)
 
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M. next said:
Yes and for further info. they wrote beside this that dLx/dx =d(yPz - zPy)/dx = 0

Do you know multivariable calculus? y and z are constants when differentiated with respect to x. Hence, the result.