Why is time scalar, not vector?

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Time is considered a scalar rather than a vector because it is independent of spatial coordinates and does not possess direction, which is a defining characteristic of vectors. While vectors have magnitude and direction and can change under coordinate transformations, time remains constant across different reference frames in classical mechanics. This independence from coordinate systems is crucial, as it aligns with the purpose of vectors to eliminate such dependencies. In special relativity, time can be treated as a component of a four-dimensional space-time vector, where its magnitude is conserved under transformations. Thus, the distinction between scalar and vector quantities is essential in understanding the nature of time in physics.
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Let's see if I think correctly first: I think a vector is a group of numbers independent of each other. What we say 3D vector means "it takes three numbers to specify a position and these numbers are not (explicitly) dependent on each other. The so called 'direction' of a vector is a visualisation that reflects this property."

If the above is correct, and since time is also independent of spatial coordinates, then why can't time be a vector?
eg: in the definition of velocity as dx/dt, x is a vector while time is a scalar. Why so?
 
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You can think of a real number as an element of a one dimensional vector space. To formally make all the definitions and distinctions needed to define the one dimensional vector space is regarded as unnecessary bother unless the one dimensional space forms a subspace of a higher dimensional space.
 
Vector and scalar are physical quantities. And Vector has Magnitude and direction, satisfying the law of vector of addition. And Time doesn't have direction, this its scalar quality. And when a vector is multiplied, divided... with scalar, the quantity obtained is vector. So, when X, displacement is vector, when differentiating with time we obtain velocity,v which is also a vector quantity. Hope it helps...
 
I got an answer, not sure if it is the complete answer:

The reason to not define time as another vector is that, in classical mechanics, the value of time is independent of reference frame. In math terms, it means that the value of time does not change under a coordinate transform and thus the length of the resultant vector magnitude might change. This defeats the very purpose of creating the concept of vector - to get rid of coordinate dependency.

In special relativity, where time does change under coordinate transform, time could be formulated as a component of a 4D space-time vector. This vector's magnitude is defined to be conserved under coordinate transform.
 
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Suppose ,instead of the usual x,y coordinate system with an I basis vector along the x -axis and a corresponding j basis vector along the y-axis we instead have a different pair of basis vectors ,call them e and f along their respective axes. I have seen that this is an important subject in maths My question is what physical applications does such a model apply to? I am asking here because I have devoted quite a lot of time in the past to understanding convectors and the dual...

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