Why only rays 2 and 5 are considered in thin film interference

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As shown in the diagram , why only ray 2 and 5 are considered? When ray 4 strikes the top interface from underneath, some is reflected. Why this ray is not considered?
 
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Of course, you may calculate higher orders (4 reflects, then travels parallel to 3 - call it 3A, then 3A reflects from bottom surface, making 4A ray, which then refracts to 5A).

Two issues:
1. every such reflection is much dimmer, than previous ones. So the interference pattern from the first order is the most visible;
2. phase shift 5-5A is exactly the same, as as 2-5. Constructive interference occurs when 2-5 phase shift is n*2π. For 5A you'll have 2*n*2π - still positive interference. But - to be honest - this argument works only for positive intereference! For the angles exhibiting negative interference, every second reflection acts opposite.
 
Secondary reflections are typically quite weak. Standard Fresnel reflections from air/glass for example is about 4-5% in power. The secondary reflections are then at most (0.05)^2 - 0.25% of the original wave. Subsequent reflections rapidly drop off in power.

Claude.