Thin Film Interference: Can You Have a Phase Difference>2pi

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Discussion Overview

The discussion revolves around the concept of phase difference in thin film interference, specifically addressing whether a phase difference greater than 2π can be considered equivalent to a smaller phase difference, such as 0.25π. The scope includes mathematical reasoning and practical implications related to coherence length and signal stability.

Discussion Character

  • Exploratory, Technical explanation, Debate/contested

Main Points Raised

  • Some participants suggest that a phase difference of 12.25π is equivalent to 0.25π due to the periodic nature of phase differences.
  • Others argue that while mathematically both values are equivalent, real-life scenarios may complicate this equivalence due to factors like coherence length of the source.
  • One participant elaborates that the bandwidth of the source can affect phase stability, leading to potential failures in cancellation and resulting in fuzzier interference fringes.
  • There is acknowledgment of the importance of coherence length in understanding the behavior of signals with large path differences.

Areas of Agreement / Disagreement

Participants express differing views on the implications of phase differences greater than 2π, with some agreeing on the mathematical equivalence while others highlight practical limitations that may affect this equivalence in real-world applications.

Contextual Notes

The discussion does not resolve the implications of coherence length and bandwidth on phase differences, leaving these aspects open for further exploration.

Riley Yakel
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If the equation for phase difference, 2(pi)(path difference/wavelength) gave you a value like 12.25pi
would that be the phase difference or would it be .25pi?
 
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Both are equivalent.
 
think about what phase difference means. If you start with a phase difference of 0.25π then complete 1 whole circle you will be back where you start, which is now 2π + 0.25π = 2.25π, one more rotation brings you to 4.25π, one more to 6.25π...you see all the possibilities that are 'equal'
 
blue_leaf77 said:
Both are equivalent.
Mathematically yes but, in real life the vector addition can go wrong because of the Coherence length of the source. Another way of looking at it is the bandwidth of the source and the phase will not be stable. This means that a signal with a large path difference will not necessarily be identical to the undelayed signal and cancellation can fail. Interference fringes get fuzzier and fuzzier for off-axis parts of the pattern.
 
sophiecentaur said:
Mathematically yes but, in real life the vector addition can go wrong because of the Coherence length of the source. Another way of looking at it is the bandwidth of the source and the phase will not be stable. This means that a signal with a large path difference will not necessarily be identical to the undelayed signal and cancellation can fail. Interference fringes get fuzzier and fuzzier for off-axis parts of the pattern.
Ah, that's a good point. I completely forget about the possibility for the source to have limited coherence length.
 

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