- #1
basty
- 95
- 0
Please take a look the below problem:
##\int^{π/2}_{-π/2}\frac{4cosθ}{3+sin2θ}dθ##
##
u = 3 + 2 sinθ, du = 2 cosθ dθ,
##
##
u(-π/2)=1, u(π/2)=5
##
##\int^{π/2}_{-π/2}\frac{4cosθ}{3+sin2θ}dθ=\int^{5}_{1}\frac{2}{u}du##
##=2ln|u|]^{5}_{1}##
##=2ln|5|-2ln|1|##
##=2ln5##
I wonder why -pi/2 = 1 and pi/2 = 5?
Note:
How to insert latex?
How do you add space in latex?
How do you align at =?
##\int^{π/2}_{-π/2}\frac{4cosθ}{3+sin2θ}dθ##
##
u = 3 + 2 sinθ, du = 2 cosθ dθ,
##
##
u(-π/2)=1, u(π/2)=5
##
##\int^{π/2}_{-π/2}\frac{4cosθ}{3+sin2θ}dθ=\int^{5}_{1}\frac{2}{u}du##
##=2ln|u|]^{5}_{1}##
##=2ln|5|-2ln|1|##
##=2ln5##
I wonder why -pi/2 = 1 and pi/2 = 5?
Note:
How to insert latex?
How do you add space in latex?
How do you align at =?