Why Short the 4kΩ Resistor in Source Transformation?

Thread starter Mdhiggenz
Start date May 30, 2013
Tags

Source Source transformation Transformation

AI Thread Summary

The discussion centers on the confusion regarding the shorting of a 4kΩ resistor in a circuit transformation. It clarifies that the resistor is not randomly shorted; rather, it is part of a Thevenin equivalent transformation involving a 5 mA current source and a 16kΩ resistor. This transformation simplifies the circuit analysis by replacing the original components with an equivalent circuit. The distinction between Norton and Thevenin equivalents is noted, confirming that the transformation in question is indeed Thevenin. Understanding this concept is crucial for accurately analyzing circuit behavior.

May 30, 2013

Mdhiggenz

Homework Statement

I am a bit confused on why they can just randomly short the 4kΩ resistor, as you can see from the first pic to the second pic.

THanks

Homework Equations

The Attempt at a Solution

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May 30, 2013

barryj

They didn't just short the 4K resistor. The 5 ma current source, the 16K resistor and the 4 k resistor was made into a norton (or is it thevinin) equivalent.

May 30, 2013

barryj

It's Thevinin, I just checked.

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