phoenixthoth
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Why is the standard deviation \sigma =\sqrt{\frac{\sum_{i=1}^{n}\left( \overline{x}-x_{i}\right) ^{2}}{n-1}} and not \sigma =\frac{\sum_{i=1}^{n}\left| \overline{x}-x_{i}\right| }{n} or at least \sigma =\sqrt{\frac{\sum_{i=1}^{n}\left( \overline{x}-x_{i}\right) ^{2}}{n}}?
I suppose that it has something to do with the normal distribution but I'm not sure in what way.
Thanks for the input.
I suppose that it has something to do with the normal distribution but I'm not sure in what way.
Thanks for the input.