Why stress is defined on 3 surface

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Discussion Overview

The discussion centers on the definition of stress on three surfaces of a cube in the context of static equilibrium and the stress tensor. Participants explore the implications of using a cube to understand stress, the conditions under which stress can be considered homogeneous, and the mathematical properties of tensors.

Discussion Character

  • Exploratory
  • Technical explanation
  • Conceptual clarification
  • Debate/contested

Main Points Raised

  • Some participants question why stress is defined on only three surfaces instead of all six, suggesting that three surfaces are sufficient for explaining stress in a small cube.
  • It is proposed that if the state of stress is homogeneous, the stresses on opposite surfaces will be equal in magnitude but opposite in direction.
  • Others argue that if the stress is not homogeneous, the stresses on one side of the cube may differ from those on the opposite side.
  • A participant emphasizes that the stress tensor is defined at each point in a material, and the Cauchy Stress Relationship can be used to determine the traction vector on a differential area of arbitrary orientation.
  • There is a discussion about the assumption that the cube is infinitesimally small, which may render differences in stress negligible even in non-homogeneous materials.
  • One participant raises a question about the preservation of angle Beta in tensors and seeks clarification on its mathematical and physical interpretation.

Areas of Agreement / Disagreement

Participants express differing views on the implications of stress homogeneity and the assumptions made when using a cube to illustrate stress. The discussion remains unresolved regarding the interpretation of tensor properties and the conditions under which stress can be considered homogeneous.

Contextual Notes

Participants note that the treatment of stress may depend on the assumptions made about the material's homogeneity and the size of the cube used in the analysis. The discussion also highlights the complexity of stress changes across differential areas in solid and fluid mechanics.

kidsasd987
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https://www.google.ca/search?q=stre...m=isch&q=stress+tensor&imgrc=xK8-tGSPxXha7M%3
This is a simple question.

-why stress is defined on 3 surfaces only instead of the entire 6 surfaces? I believe 3 surfaces are enough to explain the stress of a small cube. At static equilibrium, the opposite surfaces will experience the same stress but with the opposite direction. Is this right?
 
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kidsasd987 said:
https://www.google.ca/search?q=stre...m=isch&q=stress+tensor&imgrc=xK8-tGSPxXha7M%3
This is a simple question.

-why stress is defined on 3 surfaces only instead of the entire 6 surfaces? I believe 3 surfaces are enough to explain the stress of a small cube. At static equilibrium, the opposite surfaces will experience the same stress but with the opposite direction. Is this right?
Yes, if the state of stress is homogeneous. If not, the stresses on one side of a cube can be slightly different from the corresponding stresses on the other side of the small cube.

Using a cube is just a way to get you started understanding the stress tensor. But really, the stress tensor is defined at each point in a material. Within this context, it is better to learn the advanced treatment in which the Cauchy Stress Relationship is used to determine the "traction vector" on a differential area of arbitrary orientation at a given location in a medium.

Chet
 
Chestermiller said:
Yes, if the state of stress is homogeneous. If not, the stresses on one side of a cube can be slightly different from the corresponding stresses on the other side of the small cube.

Using a cube is just a way to get you started understanding the stress tensor. But really, the stress tensor is defined at each point in a material. Within this context, it is better to learn the advanced treatment in which the Cauchy Stress Relationship is used to determine the "traction vector" on a differential area of arbitrary orientation at a given location in a medium.

Chet

Thank you for your answer.

I understood it this way. if we find the moment then it will end up that the opposite surface will have stress components with the same magnitude but with the opposite directions because moment should be 0.so, I assume this is true
*iff the cube is under static equilibrium.
Also, I have another question.

I looked up tensor briefly, and I have a question.
Angle Beta is preserved, and I don't know how it should be. Is this a tensor property that preserved for any type of coordinate system?

if so, could you tell me that how I can mathmatically and physically interpret this.
 

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Chestermiller said:
Yes, if the state of stress is homogeneous. If not, the stresses on one side of a cube can be slightly different from the corresponding stresses on the other side of the small cube.

I think it is implicit in these pictures of cubes that the cube is infinitesimally small, so that this difference becomes negligible also if stress in the material is non-homogeneous.
 
DrDu said:
I think it is implicit in these pictures of cubes that the cube is infinitesimally small, so that this difference becomes negligible also if stress in the material is non-homogeneous.
Well, this is how they teach it to get us started. But, when we do differential force balances to obtain the Stress-Equilibrium equations in solid mechanics or the Navier Stokes equations in fluid mechanics, these stresses are taken to change from one side of the differential cube to the other, and these changes become key terms in the final differential force balance equations.
 
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