Why there is no answer when negative value is being square root?

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The discussion centers on the impossibility of taking the square root of a negative number within the realm of real numbers, as squaring any real number results in a non-negative value. This leads to the conclusion that there is no real solution for expressions like the square root of -9, which results in a "math error" on standard calculators. The introduction of complex numbers, specifically the imaginary unit 'i', allows for the square root of negative numbers, such as √-9 = 3i. Additionally, the convention that the square root symbol (√) denotes the positive root reinforces the understanding that square roots yield non-negative results in real number contexts. Consequently, calculators designed for real numbers cannot compute square roots of negative values.
wenxian
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why there is no answer when negative value is being square root?
e.g: square root of -9
when i try to find answer from calculator, ''math error '' appears..
so is there an explanation for this question??
this question may looks so weird..but i m juz asking out of curiousity..
 
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to our intuition we see that there is no number that if we multiplied by itself will be negative , since if it is negative then squaring it will result in a positive number , and the same for positive numbers , precisely we see that from the properties of the order field of real numbers that if x > 0 and y > 0 , the xy > 0 , and if x<0 and y<0 the xy<0 and we can see why x^2 > 0 or = 0 for any real number x , and hence there is no real number such that its square is negative . This led to what is Called by complex numbers , where the square root of -9 is 3i , where i is called imaginary unit and defined informally by square root of -1 .
 
Well take a number a \geq 0 and square it, obviously two positive numbers multiplied gives a positive number. Take the second case of a &lt; 0 and write it as -a for a \geq 0 and square this (-1)a \times (-1)a = (-1)(-1) \times a^2 \Rightarrow a^2 which is again positive.
Now there is a special number called i which is defined by i^2 = -1 so you can in fact find the square root of a negative number.

EDIT: sniped :)
 
The product of two positive numbers is positive and the product of two negative numbers is also positive. And, of course, the product of 0 with itself is 0. That is, for x positive, negative, or 0, x^2 is never negative.
 
wenxian said:
why there is no answer when negative value is being square root?
e.g: square root of -9
when i try to find answer from calculator, ''math error '' appears..
so is there an explanation for this question??
this question may looks so weird..but i m juz asking out of curiousity..

Your calculator is designed for real numbers only. If you had a calculator which works with complex numbers, you would get an answer.
 
so is it the same reason for the statement '' square root of x is always positive'' ??
 
wenxian said:
so is it the same reason for the statement '' square root of x is always positive'' ??

That's a convention in that \sqrt{x} is defined to be the positive solution y of the equation y^2 = x, where x \in \mathbb{R}^+.

So when you just use the √ symbol, people assume you're referring to the positive value. To refer to the negative value, you need to put the minus sign in front.
 
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