Will I Slide in My Seat During a 2km Level Turn at 400km/hr in an Airplane?

AI Thread Summary
In a level turn of 2km at a speed of 400km/hr, the frictional force between a passenger and the seat is crucial for maintaining circular motion. The required centripetal force must be calculated to determine if the static friction, with a coefficient of 0.35, is adequate to prevent sliding. Newton's first law indicates that without sufficient friction, the passenger's body will tend to move in a straight line, resulting in sliding. Understanding the relationship between speed, radius, and friction is essential for solving the problem. Ultimately, if the frictional force is insufficient, the passenger will slide in their seat.
pb23me
Messages
204
Reaction score
0

Homework Statement


you are sitting in an airplane. you have a window seat. the plane makes a level turn of 2km at speed 400km/hr. the coefficient of static friction btwn you and the seat is .35 Then they ask is the frictional force sufficient to keep you moving in a radius of 1km at a speed of 400km/hr. would you slide in your seat?


Homework Equations


(v^2/r)=a



The Attempt at a Solution

I am not sure what they mean by"is the frictional force sufficient to keep you moving in a radius of 1km" what does the frictional force have to do with keeping me moving? and I am not sure how I am supposed to go about calculating anything without an angle. i drew a force diagram see pic.
 

Attachments

  • bla.jpg
    bla.jpg
    9.9 KB · Views: 419
Physics news on Phys.org
You're parsing the statement wrong. It's, "is the frictional force enough to keep you moving in a radius of 1 km." Remember that a certain amount of centripetal force is required to maintain circular motion at a certain radius and a certain speed.

Remember also Newton's first law. Although the plane is accelerating (curving), your body wants to keep going in a straight line. The friction with the seat is what is providing the centripetal force that keeps you moving in a circle. If it is insufficient, well...you will slide tangentially to the curve.
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Collision of a bullet on a rod-string system: query'
In this question, I have a question. I am NOT trying to solve it, but it is just a conceptual question. Consider the point on the rod, which connects the string and the rod. My question: just before and after the collision, is ANGULAR momentum CONSERVED about this point? Lets call the point which connects the string and rod as P. Why am I asking this? : it is clear from the scenario that the point of concern, which connects the string and the rod, moves in a circular path due to the string...
Thread 'A cylinder connected to a hanging mass'
Let's declare that for the cylinder, mass = M = 10 kg Radius = R = 4 m For the wall and the floor, Friction coeff = ##\mu## = 0.5 For the hanging mass, mass = m = 11 kg First, we divide the force according to their respective plane (x and y thing, correct me if I'm wrong) and according to which, cylinder or the hanging mass, they're working on. Force on the hanging mass $$mg - T = ma$$ Force(Cylinder) on y $$N_f + f_w - Mg = 0$$ Force(Cylinder) on x $$T + f_f - N_w = Ma$$ There's also...
Back
Top