Winch Physics: Finding Rates of Change in Vertical and Horizontal Directions

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SUMMARY

The discussion focuses on calculating the rates of vertical and horizontal change for a winch system involving a pipe being pulled at a rate of -0.3 m/s. The relevant equations include the Pythagorean theorem, x² + y² = s², and the relationship between the rates of change, x dx/dt + y dy/dt = s ds/dt. When the vertical position y is 6 meters, the task is to determine the values of dx/dt and dy/dt, which represent the horizontal and vertical rates of change, respectively. The solution involves resolving the pulling velocity into its vertical and horizontal components.

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  • Basic understanding of trigonometric relationships in right triangles.
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Homework Statement


A winch at the top of a 15 meter tall building pulls a pipe of length 15 meters. The winch pulls the rope in at the rate of -0.3 m/s. Find the rate of vertical change and the rate of horizontal change at the upper end of the pipe when y = 6 meters.


Homework Equations


x^2 + y^2 = s^2
x dx/dt + y dy/dt = s ds/dt

The Attempt at a Solution



The question is what is dx/dt and what is dy/dt. So I need two equations to relate the two.
I have about two pages full in my notebook, it's probably better that I not share them?
 
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So basically, the pipe starts horizontally and is then rotated to be vertical?

The rope is always pulling at velocity with magnitude v = 0.3 m/s, and one has to resolve the rope velocity into vertical and horizontal components.
 
Thank You!
 

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