Winch Physics: Finding Rates of Change in Vertical and Horizontal Directions

[misterpockets]

Homework Statement

A winch at the top of a 15 meter tall building pulls a pipe of length 15 meters. The winch pulls the rope in at the rate of -0.3 m/s. Find the rate of vertical change and the rate of horizontal change at the upper end of the pipe when y = 6 meters.

Homework Equations

x^2 + y^2 = s^2
x dx/dt + y dy/dt = s ds/dt

The Attempt at a Solution

The question is what is dx/dt and what is dy/dt. So I need two equations to relate the two.
I have about two pages full in my notebook, it's probably better that I not share them?

 

[Astronuc]

So basically, the pipe starts horizontally and is then rotated to be vertical?

The rope is always pulling at velocity with magnitude v = 0.3 m/s, and one has to resolve the rope velocity into vertical and horizontal components.

 

[misterpockets]

Thank You!