Wind Power Vehicle Traveling Down Wind Faster Than The Wind

AI Thread Summary
The discussion centers on the feasibility of a wind-powered vehicle traveling faster than the wind itself, a concept known as Directly Downwind Faster Than The Wind (DDWFTTW). Participants share insights on past experiments, including a full-scale model that achieved notable speeds, and debate the mechanics involved in achieving such speeds, particularly when moving at angles to the wind. The conversation highlights the theoretical underpinnings of the vehicle's propulsion system, which utilizes wheels to drive a propeller for downwind travel and a turbine for upwind movement. Additionally, there is a focus on the efficiency of these systems and the potential for future developments in wind-powered vehicle design. Overall, the thread emphasizes ongoing interest and research in this area of physics and engineering.
  • #101
Thank you A.T. and rcgldr for all of your patient explanations and demos. I love this stuff and I am sure my students will also. For most of my students this really will have to be learned from hands on learning projects. Oh, and even my wife, a librarian is getting into this!
 
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  • #102
Fun Value said:
Thank you A.T. and rcgldr for all of your patient explanations and demos. I love this stuff and I am sure my students will also. For most of my students this really will have to be learned from hands on learning projects. Oh, and even my wife, a librarian is getting into this!

Will you build a cart and demonstrate it in class?
 
  • #103
Here is another question I have.

If I put brakes on a free spinning wheel, will the wheel stop faster when I put the brakes near the edge of the wheel than when I put the brakes near the center of the wheel, assuming constant force from the brakes? I would tend to think that when I apply them closer to the edge, it would slow down faster, and as long as the ratio of speed at contact point x force stays the same, it would stop in the same time. Essentially as long as the power is the same, J/s, that is how much kinetic energy the wheel will lose. Is this idea wrong or not with the spinning wheel and brakes example?

If I read about the work-energy principle, in my understanding it says that:

http://hyperphysics.phy-astr.gsu.edu/hbase/work.html

The change in an objects kinetic energy is equal to the work done on the object. So to make the cart move faster than the wind, ie to increase the kinetic energy of cart, work has to be done on it, it's not just force. Doesn't this also mean that as long as the engine is doing 500W of work, the objects kinetic energy is increasing at a rate of 500 J/s, no matter what the gearing is?

On the other hand these same questions can be asked about the Yo-Yo or the tumbleweed example, yet I can sort of understand why they move faster than the string is pulling or wind is pushing. What is the big picture?


Is there something wrong in the tumbleweed pdf or does the author generally have a bad reputation with applying physics the wrong way?
 
  • #104
chingel said:
If I put brakes on a free spinning wheel, will the wheel stop faster when I put the brakes near the edge of the wheel than when I put the brakes near the center of the wheel, assuming constant force from the brakes?

Yes, if we assume constant force from the brakes (no brake fading, etc.), the wheel will slow down much more rapidly if I apply the force at a greater radius. We can see that in two different ways. From a force point of view, we would be applying twice as much slowing torque if we apply the force at twice the initial radius.

From an energy point of view, we can see that we're doing much more work "against" the wheel because we're applying the same force against a faster moving point on the wheel (power = energy/time = force x velocity).

I would tend to think that when I apply them closer to the edge, it would slow down faster, and as long as the ratio of speed at contact point x force stays the same, it would stop in the same time.

You're correct.

If I read about the work-energy principle, in my understanding it says that:

http://hyperphysics.phy-astr.gsu.edu/hbase/work.html

The change in an objects kinetic energy is equal to the work done on the object. So to make the cart move faster than the wind, ie to increase the kinetic energy of cart, work has to be done on it, it's not just force.

Still correct.

Doesn't this also mean that as long as the engine is doing 500W of work, the objects kinetic energy is increasing at a rate of 500 J/s, no matter what the gearing is?

Yes. But we have to be careful - we may be losing 500 J/s of energy to aerodynamic drag, rolling resistance, etc. In that case the engine could do 500 J/s all day without the car ever accelerating.

Is there something wrong in the tumbleweed pdf or does the author generally have a bad reputation with applying physics the wrong way?

I read the original document. It was riddled with shamefully wrong statements. I know he's re-written it at least once. I don't care to grade every version of it for him. But I am happy to answer any questions you have.
 
  • #105
spork said:
But I am happy to answer any questions you have.

Can you answer my question?

Where can I find Nikos's comments on the experiment?

:wink:
 
  • #106
OmCheeto said:
Can you answer my question?

I'll certainly try.

Where can I find Nikos's comments on the experiment?

Do you mean professor Nikos Mourtos?
 
  • #107
spork said:
I'll certainly try.



Do you mean professor Nikos Mourtos?

Is there more than one Nikos that worked on the project?
 
  • #108
OmCheeto said:
Is there more than one Nikos that worked on the project?

You're talking about someone that worked on the project?
(let's see how long we can answer a question with another question)


I don't know that you can read his opinions or comments about the project anywhere. I certainly don't recall seeing them. I'm quite certain he doesn't know how it works, and I guess it'd be a coin toss as to whether he believes it works.

Why do you ask about his comments in particular?
 
  • #109
spork said:
You're talking about someone that worked on the project?
(let's see how long we can answer a question with another question)


I don't know that you can read his opinions or comments about the project anywhere. I certainly don't recall seeing them. I'm quite certain he doesn't know how it works, and I guess it'd be a coin toss as to whether he believes it works.

Why do you ask about his comments in particular?

To quote Leonard; "Fascinating"

10-26-2009, 04:43 PM
ThinAirDesigns ThinAirDesigns is offline
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Join Date: Dec 2008
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San Jose State University Aero Professor and Stanford Phd Dr. Nikos Mourtos along with a team of students and advisors have taken on a project to construct and document DDWFTTW in a more thorough way than ever before. Their goal is to achieve a documented 2x windspeed DDW.

Follow their blog at www.fasterthanthewind.org
http://www.boatdesign.net/forums/pr...ctly-downwind-faster-than-wind-25527-10.html"

and now, fasterthanthewind.org, has no mention of his existence?

sorry. You can PM the mentors/admin, and have them delete this post, as I have, on many occasions stated, that (I am of course paraphrasing, as I'm old, and have not a clue what I originally stated); "This is the most incredibly mindboggling physics homework problem in the world"

:smile:
 
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  • #110
OmCheeto said:
and now, fasterthanthewind.org, has no mention of his existence?

We set out to take this project on with a group of SJSU aero students. Dr. Mourtos was their professor - and agreed to the project. And that was about the end of it. One of the students took it upon himself to start working with us relatively late in the project. The others were effectively no-shows. Neither they nor the professor contributed in any way to the project.

Because we had accepted money from sponsors to accomplish a stated goal, JB and I saw to it that the project was completed.

But if it eases your concerns in any way - I strongly suspect he still exists.
 
  • #111
spork said:
We set out to take this project on with a group of SJSU aero students. Dr. Mourtos was their professor - and agreed to the project. And that was about the end of it. One of the students took it upon himself to start working with us relatively late in the project. The others were effectively no-shows. Neither they nor the professor contributed in any way to the project.

Because we had accepted money from sponsors to accomplish a stated goal, JB and I saw to it that the project was completed.

But if it eases your concerns in any way - I strongly suspect he still exists.

Why of course he does. I checked him out on facebook. I didn't try an befriend him. I figured he had way too many dd'er fans chasing him.

But I did just find a paper written by one of http://www.engr.sjsu.edu/nikos/projectsMSAE.htm" students:

Unfortunately, it's a 125 page pdf, and I was supposed to be in bed about 3 hours ago, so I don't have time at the moment to read much.

zzzzzzz:zzz:zzz:zzz:
 
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  • #112
OmCheeto said:
But I did just find a paper written by one of http://www.engr.sjsu.edu/nikos/projectsMSAE.htm" students:

Unfortunately, it's a 125 page pdf

That paper is incidental to the project. We take no credit or blame for it.

Incidentally, I think you'll find there are fewer than 30 pages to read. But I couldn't force myself to read much more than the abstract. The 17.5 foot propeller seems to have become a 16 inch propeller according to this paper.
 
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  • #113
spork said:
Will you build a cart and demonstrate it in class?
Depends on the time and their motivation. If they are highly motivated I might be able to demonstrate it and expect them to build their own on their own time while we move on. I like to cover the entire text in order and usually the all important high tech stuff needed now days comes near the end. I do plan to have them watch AT's U.tube presentations of ATPFTTP and UTRFTTR and at least build those things.
 
  • #114
I don't know if spork mentioned it, but he does have a series of videos that tell how to build the small cart they used on the treadmill. Look under the name of spork33 on YouTube. I believe the parts should run under $40.00.
 
  • #115
Fun Value said:
Depends on the time and their motivation. If they are highly motivated I might be able to demonstrate it and expect them to build their own on their own time while we move on. I like to cover the entire text in order and usually the all important high tech stuff needed now days comes near the end. I do plan to have them watch AT's U.tube presentations of ATPFTTP and UTRFTTR and at least build those things.
The paper and ruler videos are not mine, but from someone who posts as "Michael C". My youtube channel contains some schematic animations:
http://www.youtube.com/user/eyytee#g/u

Personally I think it would be nice if you would do Michael's experiments live with the students, so they can see that it is not a trick. But you should show the nicely made ruler video first, and stop it after the puppets present their answers. Then let the students make their predictions.

Building your own propeller model and testing it on a treadmill is of course a more advance project. But useful to teach Galilean Relativity. Michael has a nice video on that too:

https://www.youtube.com/watch?v=9Yt4zxYuPzI
 
  • #116
But then what is the correct way of thinking about the cart moving faster than the wind, and also the Yo-Yo and tumbleweed? What is the most intuitive and logical explanation?
 
  • #117
chingel said:
But then what is the correct way of thinking about the cart moving faster than the wind, and also the Yo-Yo and tumbleweed? What is the most intuitive and logical explanation?

We have never found that any given explanation is better than another overall. Each person that gets it seems to find one more intuitive while others claim that one makes no sense, and think another is more intuitive. Some are certain that none are intuitive, and that DDWFTTW is impossible.
 
  • #118
Thank you Subductionzon and A.T. I am taking your advice. I am going to try to build my own this summer and demonstrate it to my students next fall. I have yet not looked at Spork's videos, but plan to asap. Right now it seems to me that maybe the most difficult part is the gear-box - one that changes direction from the plane of the wheels to a perpendicular plane so as to run the propeller. I thought I might find one at the local hobby shop, but they didn't have one. I guess I might have to make my own. Wonder if I can make it highly efficient.
 
  • #119
Fun Value said:
Right now it seems to me that maybe the most difficult part is the gear-box - one that changes direction from the plane of the wheels to a perpendicular plane so as to run the propeller. I thought I might find one at the local hobby shop, but they didn't have one. I guess I might have to make my own. Wonder if I can make it highly efficient.

For my first one, I purchased two bevel gears and made the gear box on a mill from Delrin. In the videos though, I use a tail-rotor gearbox from an R/C heli. I give the part numbers and source in the video as well.
 
  • #120
spork said:
We have never found that any given explanation is better than another overall. Each person that gets it seems to find one more intuitive while others claim that one makes no sense, and think another is more intuitive. Some are certain that none are intuitive, and that DDWFTTW is impossible.

But what are the explanations? One is that you can view the propeller as two sails moving at an angle and they also rotate. What are the others?
 
  • #121
chingel said:
But what are the explanations?
One is that when you have two media moving at different speeds, and a device that extracts energy from the relative movement of those two media (by interacting with the media), then it is possible to construct such a device so it can continue to extract energy from the relative movment of the two media even when the devices speed is greater than the relative speed of the two media. The under the ruler cart, sailcraft like ice boats, and DDWFTTW carts, are examples of such devices. The limit of speed is related to how much the device slows the relative speed of the two media (if it slows the relative speed to zero, it can't extract energy), and when energy ouput to overcome the factors related to speed equals energy input.
 
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  • #122
Just a nitpick; this:
if it slows the relative speed to zero, it can't extract energy

should read "once it slows the relative speed to zero, it can't more extract energy."
 
  • #123
The extracting energy from two different moving media doesn't really mean anything. It isn't really an explantion. It is like asking how a car works and then you get an answer that it extracts energy from a chemical reaction. Ok, but how?
 
  • #124
chingel said:
The extracting energy from two different moving media doesn't really mean anything. It isn't really an explantion. It is like asking how a car works and then you get an answer that it extracts energy from a chemical reaction. Ok, but how?

You're kind of right. It doesn't give you the "how", but it does show you that it's not energy for free. You have wind that had energy, and you slow that wind down. That energy has to go somewhere. It goes into moving/accelerating the cart, and is ultimately lost to heat.

So again, that by itself doesn't give you the how, but it shows that we're not talking about a perpetual motion machine. That means it's just an engineering problem at that point - not a matter of re-writing physics books.
 
  • #125
chingel said:
The extracting energy from two different moving media doesn't really mean anything. It isn't really an explanation.
It's all there is to say about where the energy is coming from.

chingel said:
It is like asking how a car works and then you get an answer that it extracts energy from a chemical reaction. Ok, but how?
If you are not happy with such answers then you should not insist on explanations in terms of energy.
 
  • #126
chingel said:
The extracting energy from two different moving media doesn't really mean anything.
Two points being covered in my previous post:

1 - Say there's only one moving media the cart can interact with, for example wind but frictionless ground. The cart will eventually move at wind speed but no faster.

2 - The two media's relative speed with respect to each other provides an energy source that isn't directly related to the speed of the DDWFTTW cart. The cart can be designed to extract energy from the relative movement of the two media, even when the cart's speed is faster than the relative speed between the two media.

The BB cart achieved 2.8x wind velocity. If you switched the frame of reference to be the air, then the BB cart acheived -1.8x relative ground velocity, so from either frame of reference, the cart speed is faster than the relative speed between the two media.

chingel said:
Ok, but how?
I think that the yo-yo case is somewhat intuitive since the outcome is what most people would expect. If you pull a yo-yo on the ground by pulling it's string horizontally, the yo-yo moves faster than the string. Then you could point out that if the ground didn't have any friction, then the yo-yo could would only move as fast as the string, so it's clear that the the yo-yo needs to interact with both the ground and string, which are the two media moving at different speeds in this example, in order for the yo-yo to move faster than the string. The energy input is the force times distance the string moves. The energy output is the gain in linear and angular kinetic energy of the yo-yo as it accelerates (plus losses due to rolling resistance, and friction, which end up as heat).
 
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  • #127
A.T. said:
It's all there is to say about where the energy is coming from.


If you are not happy with such answers then you should not insist on explanations in terms of energy.

Yes that's all nice and the only place it could possibly extract energy, but it doesn't explain anything, what, how? It is very unsatisfying. I cannot just go and start extracting energy from two different medias, I have to have some sort of a way or a mechanism of doing it.

I also have the same problem with the Yo-Yo. If the middle part is freewheeling, the Yo-Yo goes at the speed of the string, but when you connect it rigidly to the outer parts, it uses their energy to spin against the string and work itself up. Something must be wrong with my idea and it is bothering me.

Maybe a better way would be thinking about it like some sort of a fulcrum? If the Yo-Yo is hexagonal for example, the ground is the fixed point of the fulcrum, the force is applied somewhere in between the ground and center of the Yo-Yo and since the center of the Yo-Yo is further along the lever it would move faster. But this would mean that the closer the point where the string applies it's force is to the ground the faster it would move, but that is not the case with the Yo-Yo. Or maybe I'm thinking about it wrong?
 
  • #128
chingel said:
Yes that's all nice and the only place it could possibly extract energy, but it doesn't explain anything, what, how? It is very unsatisfying. I cannot just go and start extracting energy from two different medias, I have to have some sort of a way or a mechanism of doing it.

This is exactly what we've been telling you. If you insist on asking where does the energy come from, we'll tell you where the energy comes from (and you'll tell us that's not satisfying). If you want to know how it works - ask how it works - and then think about the answers.

I also have the same problem with the Yo-Yo. If the middle part is freewheeling, the Yo-Yo goes at the speed of the string, but when you connect it rigidly to the outer parts, it uses their energy to spin against the string and work itself up.

This is strictly a kinematics problem. It does not rely on the yo-yo's mass, momentum, or energy. If you pull the yo-yo by it's spindle it will roll itself up the string. The problem is that our intuition tells us that wheels rotate about their axles. In the ground frame, the wheel is rotating about the point of contact with the ground. So you're pulling on the yo-yo well above it's pivot point (the ground) and it's doing the natural thing - rotating about that pivot point toward the thing that's pulling it.

Maybe a better way would be thinking about it like some sort of a fulcrum? If the Yo-Yo is hexagonal for example, the ground is the fixed point of the fulcrum, the force is applied somewhere in between the ground and center of the Yo-Yo and since the center of the Yo-Yo is further along the lever it would move faster. But this would mean that the closer the point where the string applies it's force is to the ground the faster it would move

I should have read ahead. That is 100% correct.

...but that is not the case with the Yo-Yo.

It is the case with a yo-yo. Try it.
 
  • #129
Yes in the end the energy can only come from the wind, and since there are videos of it going faster than the wind, it does extract it somehow. What I would like to know is how does it do it, where does the energy come from when the cart is up to wind speed?

Isn't it that the smaller the diameter of the center part, the faster the yo-yo goes up the string? But in the case of a fulcrum, the closer you are to the pivot point, assuming constant speed of the string, the faster the top of the lever moves, no?
 
  • #130
chingel said:
Yes in the end the energy can only come from the wind, and since there are videos of it going faster than the wind, it does extract it somehow. What I would like to know is how does it do it, where does the energy come from when the cart is up to wind speed?

That depends on which frame you are looking at the problem from. From the ground frame, the energy comes from the fact that as the cart goes by, the air is slowed down. From the cart frame, the energy comes from the fact that the ground is applying a force to the wheels at a nonzero velocity.

chingel said:
Isn't it that the smaller the diameter of the center part, the faster the yo-yo goes up the string? But in the case of a fulcrum, the closer you are to the pivot point, assuming constant speed of the string, the faster the top of the lever moves, no?

For a yo-yo, the larger the diameter of the center part, the faster it will move (seriously). Look at this in the limiting case - if the center part had zero diameter, such that no string wound up, the yo-yo would simply roll at the same speed the string was pulled. That is clearly the slowest it will go. Now, if the center part has half the diameter of the outer part of the yo-yo, the yo-yo has to move faster, since as the string is pulled and the yo-yo moves, the string is being shortened as it is wound up. In the case of the center having half of the diameter of the outside, the yo-yo will travel at twice the speed at which the string is pulled. If the center part is 90% of the diameter of the outside, the yo-yo will travel ten times faster than the string is pulled (assuming no slipping).
 
  • #131
chingel said:
Yes in the end the energy can only come from the wind, and since there are videos of it going faster than the wind, it does extract it somehow. What I would like to know is how does it do it, where does the energy come from when the cart is up to wind speed?
Although the cart is moving at or faster than wind speed, the air accelerated by the propeller is moving slower than wind speed, and that air is slowing down part of the wind, and that is the source of the energy. All of this is from a ground based frame of reference.

From the carts frame of reference, the forward force (from the wheels) on the surface of the Earth is slowing down the Earth (relative to the cart) a very tiny bit, and that is the source of energy that allows it to accelerate the relative headwind.

From the air's frame of reference, again the forward force (from the wheels) on the surface of the Earth is slowing down the Earth (relative to the air) a very tiny bit, and that is the source of energy that allows the propeller to accelerate the air.

The DDWFTTW cart is like a hybrid car, except that the braking energy is being used to drive the propeller as opposed to charging a battery. This only works if there's a tailwind to supply more energy than is consumed by the braking energy.

chingel said:
Isn't it that the smaller the diameter of the center part, the faster the yo-yo goes up the string?
If the center part (and string) had zero diameter there would be no winding of the string, and the yo-yo would move at the same speed as the string.

To cover all the cases from a yo-yo like device, imaging that there are two hubs on the outside of the yo-yo and that the hubs rest on a pair of rails, with a rail on each side of the yo-yo, with the yo-yo otherwise suspended in air, only resting on the hub rails. If the string is wound above the center axle and the string is pulled forwards, the yo-yo moves at less than string speed, and this is the equivalent of a negative advance ratio. If the string slides on the center axle, then it's the equivalent of a zero diameter axle, and a zero advance ratio, and the yo-yo moves at the same speed as the string. If the axle diameter is smaller than the hub diameter, the yo-yo moves faster than the string, the equivalent of advance ratio greater than zero and less than one. If the axle and hub diameters are the same, the yo-yo doesn't move unless it slides, this is an advance ratio of 1. If the axle diameter is greater than the hub diameter, but less than double the hub diameter, the yo-yo moves away as the string is pulled, but faster than the string, an advance ratio greater than 1 but less than 2. If the axle diameter is double the hub diameter, the yo-yo moves away at the same speed as the string, advance ratio of 2. If the axle diameter is greater than double the hub diameter, the yo-you moves away, but at less than string speed, an advance ratio greater than 2.

The closer ratio between the axle and hub diameters is to 1, the faster the yo-yo will move relative to the string, until the ratio gets too close to 1 and then the yo-yo "stalls" and won't move without sliding.
 
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  • #132
I would tend to think the smaller the diameter of the center part, the faster the yo-yo moves, because when the surface of the center part moves at 1 cm/s, if the outer diameter is twice of it it moves at 2 cm/s, 3 cm/s if triple etc. Since they are connected they have to make the same amount of turns and a bigger wheel means the surface has to move faster to make the turns at the same rate. But in this case the fulcrum analogy doesn't apply, because it produces different results, it goes faster the further away the point where you apply the force is from the pivot point, or not? And why doesn't it apply, because if the yo-yo is hexagonal, why can't I view it as a lever?

The places where it ultimately must get the energy are undeniably correct since the cart is actually moving faster than the wind and has to get it from somewhere. But what happens at windspeed, how does it do it?
 
  • #133
chingel said:
The places where it ultimately must get the energy are undeniably correct since the cart is actually moving faster than the wind and has to get it from somewhere. But what happens at windspeed, how does it do it?

You must stop asking "but where does the energy come from when at wind speed" if you want to know how it happens, and start asking "HOW?". I see you have asked "how?" now a couple of times. I have to run, but I will gladly answer that if someone hasn't beaten me to it by the time I return.
 
  • #134
chingel said:
I would tend to think the smaller the diameter of the center part, the faster the yo-yo moves, because when the surface of the center part moves at 1 cm/s, if the outer diameter is twice of it it moves at 2 cm/s, 3 cm/s if triple etc.
Take the triple case. Assume the string moves at +1 cm/s, then the yo-yo moves in the same direction as the string at +1.5 cm/s second (relative to the ground). From the yo-yo's perpective, the ground moves at -1.5 cm/s, the inner diameter moves at -.5 cm/s second (1/3rd the outer diameter surface speed), and string moves at -1 cm/s.

In the double case, the yo-yo moves at twice the string speed (relative to the ground) at +2 cm/s (relative to the ground). From the yo-yo's perpective, the ground moves at -2 cm/s, the inner diameter moves at -1 cm/s second (1/2 the outer diameter surface speed), and string moves at -1 cm/s.

The places where it ultimately must get the energy are undeniably correct since the cart is actually moving faster than the wind and has to get it from somewhere. But what happens at windspeed, how does it do it?
As mentioned above, from a ground based frame of reference, the propeller's thrust slows down the wind, even when the cart is moving at faster than wind speed. Using the BB's stated advance ratio of .8, and max speed of 2.8x wind speed, then if wind speed is 10 mph, cart speed is 28 mph. From the cart frame of reference, ground speed is -28 mph, prop thrust speed is (-28 x .8 =) -22.4 mph, and wind speed is (-28 + 10 = ) -18 mph, and the air affected by the propeller is accelerated (-22.4 - -18 =) -4.4 mph. From a ground frame of reference, the wind speed is +10 mph, the cart speed is +28 mph, the propeller thrust speed is (28 - 22.4 = ) +5.6 mph, slower than the +10 mph wind speed. So the air affected by the propeller is slowed down by 4.4 mph.
 
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  • #135
chingel said:
...how does it do it?

There are a bunch of ways to describe this, but let's take a simple kinematic approach first...

First let's imagine our cart was submersed in Jello and the prop has a very fine pitch (in other words it only tries to screw it's way through the jello by about 1 foot per rotation). So now we move this entire block of jello that the cart is in - but it's wheels are still rolling on the stationary ground. By pushing the jello forward, we end up pushing the cart forward too - and that makes the propeller rotate. So let's imagine that we gear the wheels pretty low so we have to push the cart forward 100' to make the prop do one full turn.

See what happens there? We push the jello forward 100', the prop makes one full turn, so the cart moves forward 100' with the jello *plus* the one foot its prop pulled it through the jello.

So if we do this over a period of one minute, the jello goes 100 feet per minute. But the cart goes 101 feet per minute (because it pulled itself forward in the jello). We're now going down jello faster than the jello - right?
 
  • #136
spork said:
There are a bunch of ways to describe this, but let's take a simple kinematic approach first...

First let's imagine our cart was submersed in Jello and the prop has a very fine pitch (in other words it only tries to screw it's way through the jello by about 1 foot per rotation). So now we move this entire block of jello that the cart is in - but it's wheels are still rolling on the stationary ground. By pushing the jello forward, we end up pushing the cart forward too - and that makes the propeller rotate. So let's imagine that we gear the wheels pretty low so we have to push the cart forward 100' to make the prop do one full turn.

See what happens there? We push the jello forward 100', the prop makes one full turn, so the cart moves forward 100' with the jello *plus* the one foot its prop pulled it through the jello.

So if we do this over a period of one minute, the jello goes 100 feet per minute. But the cart goes 101 feet per minute (because it pulled itself forward in the jello). We're now going down jello faster than the jello - right?

That's an awesome way to visualize it :biggrin:

I think that's my favorite explanation yet. It makes it really obvious how it works.
 
  • #137
rcgldr said:
Take the triple case. Assume the string moves at +1 cm/s, then the yo-yo moves in the same direction as the string at +1.5 cm/s second (relative to the ground). From the yo-yo's perpective, the ground moves at -1.5 cm/s, the inner diameter moves at -.5 cm/s second (1/3rd the outer diameter surface speed), and string moves at -1 cm/s.

In the double case, the yo-yo moves at twice the string speed (relative to the ground) at +2 cm/s (relative to the ground). From the yo-yo's perpective, the ground moves at -2 cm/s, the inner diameter moves at -1 cm/s second (1/2 the outer diameter surface speed), and string moves at -1 cm/s.

I don't understand. Are you saying that the smaller the diameter of the middle part the faster it moves or the slower it moves? If the yo-yo moves 1,5 cm/s, and the middle part moves -0,5 cm, then it isn't moving up the string, it should be slipping on it? The middle part has to move faster than the string to climb it up. In the under the ruler faster than the ruler example, the smaller the diameter of the middle parts of the wheels where the big wheel applies the force, the faster it moves, or wasn't that the case?

If it moves faster when the middle part is smaller, then it would mean that the effect is different from the lever example, but why can't I view it as a lever, especially when making the yo-yo hexagonal?

The cart would indeed move along the jelly faster than the jelly. I am having difficulty imagining that when you get the cart up to jelly speed and then engage the propeller, how does the force apply, how does it not use it's own energy to propel itself? I guess it's the same principle as the yo-yo, where the wheels are pivoting around the contact point with the ground, which I am having trouble grasping.
 
  • #138
It moves faster when the middle part is larger (for the yo-yo example).
 
  • #139
rcgldr said:
Yo-yo ... take the triple case. ... (wrong string speed numbers from yo-yo frame of reference)

chingel said:
I don't understand.
My fault, the inner diameter speed and the string speed are the same, regardless of the frame of reference. The rest of the numbers were OK.

chingel said:
Are you saying that the smaller the diameter of the middle part the faster it moves or the slower it moves?
The slower it moves. If the diameter is zero, the yo-yo moves at string speed. The larger the diameter, the faster the yo-yo moves as long as it doesn't slide. If the axle diameter is the same as the yo-yo diameter, then it can only move by sliding. If the axle diameter was greater than the yo-yo diameter (assume the yo-yo is rolling on rails to allow this), the yo-yo will roll to the left when the string is pulled to the right. In both cases, the closer the ratio of inner_diameter to outer_diameter is to 1, the faster the yo-yo moves (except if they're equal to 1, the yo-yo can only move by sliding).

The formula with respect to the ground:

yo_yo_speed - string_speed = (inner_diameter / outer_diameter) x yo_yo_speed
yo_yo_speed = string_speed / (1 - (inner_diameter / outer_diameter))

Listing the case by inner_diameter to outer_diameter ratio:

1 to 3 case: yo-yo moves in the same direction as the string at +1.5 cm/s second (relative to the ground). From the yo-yo's perpective, the ground moves at -1.5 cm/s, the inner diameter and the string move at -.5 cm/s second (1/3 the ground speed).

1 to 2 case: yo-yo moves in the same direction as the string at +2.0 cm/s second (relative to the ground). From the yo-yo's perpective, the ground moves at -2.0 cm/s, the inner diameter and the string move at -1.0 cm/s second (1/2 the ground speed).

2 to 3 case: yo-yo moves in the same direction as the string at +3.0 cm/s second (relative to the ground). From the yo-yo's perpective, the ground moves at -3.0 cm/s, the inner diameter and the string move at -2.0 cm/s second (2/3 the ground speed).

3 to 4 case: yo-yo moves in the same direction as the string at +4.0 cm/s second (relative to the ground). From the yo-yo's perpective, the ground moves at -4.0 cm/s, the inner diameter and the string move at -3.0 cm/s second (3/4 the ground speed).

- - - -

3 to 2 case: yo-yo moves in the opposite direction as the string at -2.0 cm/s second (relative to the ground). From the yo-yo's perpective, the ground moves at +2.0 cm/s, the inner diameter and the string move at +3.0 cm/s second (3/2 the ground speed).
 
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  • #140
chingel said:
In the under the ruler faster than the ruler example, the smaller the diameter of the middle parts of the wheels where the big wheel applies the force, the faster it moves,
No. It moves faster when the inner diameter tends towards the outer diameter.

chingel said:
then it would mean that the effect is different from the lever example,
No. It is the same. The blue wheel just allows to apply the force on top.

chingel said:
but why can't I view it as a lever
Sure you can. See the red dashed line indicating the leverage:

[PLAIN]http://img375.imageshack.us/img375/4229/dwfttwwheel09dashedleve.gif

chingel said:
I am having difficulty imagining that when you get the cart up to jelly speed and then engage the propeller, how does the force apply, how does it not use it's own energy to propel itself? I guess it's the same principle as the yo-yo, where the wheels are pivoting around the contact point with the ground, which I am having trouble grasping.

Here the same thing at windspeed. It obvious that the air will push the paddles forward:

33lm5fq.gif
 
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  • #141
cjl said:
That's an awesome way to visualize it :biggrin:

I think that's my favorite explanation yet. It makes it really obvious how it works.

Thanks. But interestingly enough, not a word about it from chingel. I thought I was answering his question. Doesn't it at least deserve a "you're full of it"?
 
  • #142
There was this reply:
chingel said:
The cart would indeed move along the jelly faster than the jelly. I am having difficulty imagining that when you get the cart up to jelly speed and then engage the propeller, how does the force apply, how does it not use it's own energy to propel itself?
It almost sounds like a clarification might be in order; I'm wondering what chingel means by "it's own energy". To my way of thinking, the only "energy" the cart would have would be from the motion imparted by the jello.
 
  • #143
mender said:
There was this reply...

It almost sounds like a clarification might be in order; I'm wondering what chingel means by "it's own energy". To my way of thinking, the only "energy" the cart would have would be from the motion imparted by the jello.

Turns out I'm the fool. My apologies to Chingel. I missed that part because he started out by responding to another post.

Let's take it point by point:

The cart would indeed move along the jelly faster than the jelly.

Good. Now we replace the jello with air (i.e. replace the moving jello with wind). Done. We're going directly downwind faster than the wind.

I am having difficulty imagining that when you get the cart up to jelly speed and then engage the propeller...

No, no, no. We don't get it up to speed and then engage anything. The wheels are rolling against the ground at all times. The prop is geared to the wheels at all times. The prop is effectively "geared" into the jello at all times. This is now a simple kinematic puzzle like the yo-yo. We don't have to think about where the energy comes from this way.

When a 200 lb man pulls on the string of a 3 oz yo-yo, you don't worry where the energy comes from. By the same token, we don't care how big a monster it takes to push that jello along. He just does it - no matter what it takes. All we have to do is ask what motions will the wheels, prop, and cart follow when encased in that jello that moves along over the road.

how does the force apply

In the case of the jello, the jello just pushes on the back of the prop. When the jello pushes on the back of the prop, it will tend to want to turn the prop counter-clockwise (as seen from behind). But it will also want to push the prop along in the direction the jello is going. If it does push it along in the direction the jello is going, the prop HAS to turn clockwise as seen from behind - because it's geared to the wheels that way.

So there's a torque from the jello trying to turn the prop CCW and a torque on the prop-shaft (from the wheels) trying to turn it CW. Because we geared it extremely low (100 wheel turns for a singe prop turn), we know which one will win. The CCW jello torque on such a low pitched prop will be minimal. But the geared down torque from the wheels in the CW direction will be immense. So the prop moves down-jello with the jello, but it also screws its way through the jello very gradually.

how does it not use it's own energy to propel itself?

The energy comes from the giant monster playing with his food.

In the case of the wind, the energy come from uneven heating of the Earth's surface (in other words - the sun - which also has a whole lot more energy than our little cart needs).
 
  • #144
mender said:
I'm wondering what chingel means by "it's own energy".
People who have problems understanding the energy balance in DDWFTTW usually have a flawed understanding of the energy concept itself. The whole point of such brainteasers it to challenge naively intuitive folksy notions about physics, and lead to a more precise understanding. The later however requires accepting that you have a flawed understanding of certain general concepts in physics (like energy), and not just a problem with understanding this particular example.
 
  • #145
mender said:
I'm wondering what chingel means by "it's own energy".
In his earlier posts, it seemed he had the idea that the somehow the cart was extracting it's own kinetic energy as part of the input power. I thought I explained the actual source of energy in an earlier post, but in case he missed it I'll restate it here.

In all frames of reference the cart's own kinetic energy is never an input, it's always the end result of extracting energy from either the wind or the earth, depending on the frame of reference, and is designed to take advantage of the fact that there is a difference in speed between the wind and the ground, even when the cart's own speed is greater (up to a limit, which for the BB, is about 2.8x wind speed using a ground frame of reference).

From a ground frame of reference, even when the cart is moving at or faster than wind speed, the thrust from propeller (relative to ground) is moving slower than wind speed (relative to ground), and that thrust is slowing down (a portion of) the tail wind (relative to ground), and that slowing of the tail wind is the source of energy.

From the air's frame of reference, the forward force (from the wheels) on the surface of the Earth is slowing down the Earth (relative to the air) a very tiny bit, and that is the source of energy that allows the propeller to accelerate the air, and accelerate the cart until it reaches it's maximum speed.

The DDWFTTW cart is like a hybrid car, except that the braking energy is being used to drive the propeller as opposed to charging a battery. This only works if there's a tail wind that allows the cart to utilize effective gearing between wheels and propeller so that propeller thrust is greater than braking force, while at the same time propeller power output is less than braking power input, due to the greater difference in speed between cart and ground versus cart and air (when the cart is moving downwind).

The DUWFTTW (upwind) cart is like a wind mill, where the turbine (propeller) energy is being used to drive the wheels as opposed to driving a generator. This only works if there's a head wind that allows the cart to utilize effective gearing between turbine and wheels so that wheel driving force is greater than turbine drag, while at the same time wheel driving power output is less than turbine power input, due to the greater difference in speed between cart and air versus cart and ground (when the cart is moving upwind). Aerodynamic drag is greater in this case, so the maximum speed will be less than that of a DDWFTTW cart going downwind.
 
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  • #146
A.T. said:
People who have problems understanding the energy balance in DDWFTTW usually have a flawed understanding of the energy concept itself. The whole point of such brainteasers it to challenge naively intuitive folksy notions about physics, and lead to a more precise understanding. The later however requires accepting that you have a flawed understanding of certain general concepts in physics (like energy), and not just a problem with understanding this particular example.

That's a very good point, and really helps to explain the almost violent reactions we sometimes get. It's not just that this goes against intuition. It challenges people on a deeper level.
 
  • #147
I think that part of the issue is statements like a DDWFTTW cart outruns the wind that powers it, when in fact it's the difference in speed between wind and ground that powers the cart, and that the thrust from the wheel driven propeller never outruns the wind, but instead always slows down the wind, even when the cart itself is moving faster than the wind.

After this, it's just a case of explaining the design of a DDWFTTW cart, mostly how effective gearing between wheels and propeller allow the cart to achieve faster than wind speed as long as there's a difference in speed between a tailwind and the ground.
 
  • #148
How does the fulcrum example apply to the under the ruler example, where the center of the wheel is between the pivot point and the point where the force is applied? How does the center of the wheel move faster there?

The other examples are easier to understand and they should work. But I still have a problem imagining what happens when I am on a cart at windspeed and then I engage the propeller? Why doesn't all the energy used for propulsion of the air particles cause exactly as much drag at the wheels?
 
  • #149
rcgldr said:
I think that part of the issue is statements like a DDWFTTW cart outruns the wind that powers it...

Agreed. That's why I try and correct people, explaining that our cart outpaces the wind. It doesn't outrun the wind any more than a swimmer can outrun the water. We're always immersed in it.

chingel said:
I still have a problem imagining what happens when I am on a cart at windspeed and then I engage the propeller? Why doesn't all the energy used for propulsion of the air particles cause exactly as much drag at the wheels?


Again, keep in mind that we don't engage the propeller at wind speed. It's geared to the wheels from the very start. But to answer your second question - "Why doesn't all the energy used for propulsion of the air particles cause exactly as much drag at the wheels?" - that's because the cart is moving over the ground faster than it's going through the air. 10 lbs of thrust x 10 mph (through the air) is how much energy we need. 10 lbs of thrust x 20 mph (over the ground) is how much energy we get. The wheels constitute the long end of the lever. They move further over the ground than the prop moves through the air. Like any lever, we can get more force over a short distance at the shorter end of the lever.
 
  • #150
chingel said:
Why doesn't all the energy used for propulsion of the air particles cause exactly as much drag at the wheels?
Because there is no reason it should.
 
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