Power available to a wind powered vehicle traveling directly downwind

  • Context: Undergrad 
  • Thread starter Thread starter electrodacus
  • Start date Start date
  • Tags Tags
    Power Vehicle Wind
Click For Summary
SUMMARY

The discussion centers on the calculation of wind power available to a wind-powered vehicle traveling directly downwind. The key equation established is P = 0.5 * air density * area * coefficient of drag * (wind speed - vehicle speed)^3. Participants emphasized the importance of including the drag coefficient in the calculations, with a sample scenario yielding a power output of 129.6W using a wind speed of 10m/s, a vehicle speed of 4m/s, a sail area of 1m², and an air density of 1.2 kg/m³. The conversation highlights the necessity of understanding both the force acting on the vehicle and the velocity at which this force is applied.

PREREQUISITES
  • Understanding of wind power equations
  • Knowledge of air density and its impact on wind power
  • Familiarity with drag coefficients and their role in aerodynamic calculations
  • Basic principles of physics related to force and velocity
NEXT STEPS
  • Study the impact of varying drag coefficients on wind power calculations
  • Explore the relationship between wind speed and vehicle speed in aerodynamic contexts
  • Learn about the conservation of energy principles as they apply to wind-powered vehicles
  • Investigate real-world applications of wind power equations in vehicle design
USEFUL FOR

Engineers, physicists, and enthusiasts involved in renewable energy, particularly those focused on the design and optimization of wind-powered vehicles.

  • #61
electrodacus said:
What you describe is an overunity device like those electric generators powered by an electric motor and electric motor is supplied by the electric generator and on top of that you can also power a light bulb.
As I already mentioned not understanding energy conservation.
Incorrect. The power extracted never exceeds the power available per the equation. At this point I'm going to lock the thread since you seem to be uninterested in learning how these devices actually work and we're stuck in a loop where you just keep referring back to the wrong equation.
 
  • Like
Likes   Reactions: dlgoff, berkeman and erobz

Similar threads

  • · Replies 69 ·
3
Replies
69
Views
16K
  • · Replies 5 ·
Replies
5
Views
2K
Replies
5
Views
3K
  • · Replies 169 ·
6
Replies
169
Views
15K
  • · Replies 175 ·
6
Replies
175
Views
35K
  • · Replies 57 ·
2
Replies
57
Views
14K
  • · Replies 14 ·
Replies
14
Views
2K
  • · Replies 10 ·
Replies
10
Views
3K
  • · Replies 73 ·
3
Replies
73
Views
29K
  • · Replies 124 ·
5
Replies
124
Views
20K