Wire coil in decreasing magnetic field

AI Thread Summary
To determine the current through the resistor in the wire coil, the magnetic flux must be calculated using the formula Flux = B⋅dA, where B is the magnetic field strength and dA is the area of the coil. The magnetic field decreases from 2 T to 0 T over 10 ms, resulting in a rate of change of -200 T/s. According to Faraday's law of induction, the induced electromotive force (EMF) can be calculated, which is equal to the negative rate of change of magnetic flux. The current through the resistor can then be found using Ohm's law, I = V/R, where V is the induced EMF and R is the resistance of 5 Ω. This approach effectively links the concepts of magnetic flux, Faraday's law, and Ohm's law to solve the problem.
Pete Panopoulos
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Homework Statement


A wire coil of 2 cm with 10 turns is in a magnetic field of 2 T. The field is perpendicular to the plane of each turn of the coil. The coil is wired in series with resistor of 5 Ω. The field drops at a constant rate to 0.0 T in 10 ms. What is the current through the resistor?

Homework Equations


V=IR
Possibly F=ILxB ?
Magnetic Flux= B⋅dA = Bπr2

The Attempt at a Solution


I=V/R

We know that the magnetic field drops from 2T to 0T in .01 seconds, or -200T/s

and the Resistor is 5 Ω

Flux= B⋅dA = Bπ(.02)2

I'm assuming I'm missing a link to these things in my head any help would be appreciated
 
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