Word Problem Beginning Calculus

[I'm]

1. Homework Statement [/b]
A cyclist is riding on a path modeled by f(x)= 0.08x where f and f(x) are measured in miles. Find the rate of change in elevation when x = 2

Homework Equations

(f(∆x + x ) - f(x))/∆x
∆x\stackrel{lim}{\rightarrow} 0

The Attempt at a Solution

I plugged everything into the formula and got

.00008 / .0001 = .08.

Is this the correct answer?
I think I'm doing something wrong here.

 

[Дьявол]

So you got
\lim_{\triangle x \rightarrow 0}\frac{f(\triangle x+x)+f(x)}{\triangle x}

\lim_{\triangle x \rightarrow 0}\frac{0.08(\triangle x+x) - 0.08x}{\triangle x}

So yes, 0.08 is the final answer.

 

[CompuChip]

Your answer looks correct, but it appears you didn't take the limit. Instead, you just plugged in an arbitrary value for \Delta x. Just leave it as it is: what is f(x + \Delta x) - f(x) when you plug in the definition of f?

 

[Mark44]

1. Homework Statement [/b]
A cyclist is riding on a path modeled by f(x)= 0.08x where f and f(x) are measured in miles.

Make that "where x and f(x) are measured in miles."

Find the rate of change in elevation when x = 2

Homework Equations

(f(∆x + x ) - f(x))/∆x
∆x\stackrel{lim}{\rightarrow} 0

The Attempt at a Solution

I plugged everything into the formula and got

.00008 / .0001 = .08.

Is this the correct answer?
I think I'm doing something wrong here.

The answer is numerically correct, but you might need to give units, which are miles/mile. Note that the cyclist's path is a straight line whose slope can be determined merely by observation. The instantantaneous rate of change of f is going to be the same for all values of x, because the graph of f is straight line.