- 14

- 0

Here is it.

A piece of wire 10m long is cut into two pieces. On piece, of length x, is bent into the shape of a square. The other is bent into the shape of a equilateral triangle.

(a) expess the total area of a enclosed as a function of x

b. For what value is of x is this total area a minimum.

This is what I think I can figure out.

One side of the square is s = x/4

One side of the triangle is s = (10 -x)/3

Area of Square is A= lw

Area of Triangle is A = 1/2bh

How do I go from here.

TIA

I may be totally wrong