Work and Energy of weightlifter

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Homework Help Overview

The problem involves calculating the total energy expended by a weightlifter lifting a barbell, considering efficiency in energy use. The subject area includes work and energy principles in physics.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the calculation of work done per repetition and the impact of efficiency on total energy expenditure. There are attempts to multiply work done by the number of repetitions and to factor in efficiency, leading to questions about the correctness of these calculations.

Discussion Status

The discussion is ongoing, with participants exploring different interpretations of how to incorporate efficiency into their calculations. Some guidance has been offered regarding the application of efficiency, but there is no explicit consensus on the correct method to arrive at the final answer.

Contextual Notes

Participants are working under the constraints of a homework assignment, which may limit the information available for their calculations. There is also a follow-up question regarding caloric intake related to the energy expenditure, adding another layer to the problem.

paulsberardi
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Homework Statement


A weightlifter works out at the gym each day. Part of her routine is to lie on her back and lift a 44 kg barbell straight up from chest height to full arm extension, a distance of 0.54 m.

Homework Equations


If the weightlifter does 24 repetitions a day, what total energy does she expend on lifting? Assume 25 % efficiency.

The Attempt at a Solution


I looked at it, and could only see that the only change in energy is work. Work is 230J per repetition. I tried multiplying 230J by 24 in order to get the answer, but it was not correct.
 
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What about the efficiency? Only 25% efficiency means that 3/4 of the work done is wasted, and only 1/4 of it goes to actually lifting the weight.
 
Ya, I took the 230 J and multiplied it by 24, then by .25 but it won't accept the answer
 
paulsberardi said:
Ya, I took the 230 J and multiplied it by 24, then by .25 but it won't accept the answer

That's because multiplying it by 0.25 is not the right thing to do. You should read my post again, more carefully.
 
Ok I got the answer, its 22,000 Joules.
Part 3 of the question: How many 480 Calorie donuts can she eat a day to supply that energy?
I thought I could just convert the joules to calories by dividing by 4.184, then divide again by 480 to get number of donuts.
 

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