Work calculation for isothermal compression

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The discussion focuses on calculating work done during isothermal compression of an ideal gas using two formulas: W=n*R*T*ln(V_f/V_i) and W=p*(V_f-V_i). The user initially attempted to apply the isothermal work formula but found it incorrect, then tried the constant-pressure formula with similar results. A key point raised is that the problem requires the work done by an external agent, not the gas itself, and questions whether the external work should be considered positive or negative. Additionally, inconsistencies in the provided data regarding the ideal gas law are highlighted, suggesting a potential error in the problem's parameters. Clarification on these points is essential for solving the problem correctly.
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Homework Statement


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Homework Equations


Work done by an ideal gas, isothermal process: W=n*R*T*ln(V_f / V_i)
Work, constant-pressure process: W=p*(V_f - V_i)

The Attempt at a Solution


I first tried plugging n=1, R=8.31, T=273.15, V_f=17.5 L, V_i=24 L into the first equation and it didn't work.

I then tried the constant-pressure formula with the corresponding values given from the problem (p=.937 atm, V_f=17.5 L, V_i=24 L) and it didn't work either.

This problem seems pretty straight forward but I can't get the right answer. Help?
 
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The work formula you used is for the work of the gas. The problem asks the work of an external agent. Is the external work positive or negative?

The data given are not consistent with the ideal gas law. 1 mol oxygen at 0 °C can not have 24 L volume at 0.937 atm pressure. Have you copied it correctly?

ehild
 

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