Work done by a constant torque equation DOESN'T give me angular speed Help

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Homework Help Overview

The discussion revolves around the calculation of angular speed using the work-energy principle in the context of rotational motion. The original poster presents a problem involving torque, inertia, and angular displacement, seeking to find the final angular speed.

Discussion Character

  • Exploratory, Assumption checking, Problem interpretation

Approaches and Questions Raised

  • Participants discuss the necessity of converting angular displacement from revolutions to radians, with several posts emphasizing this conversion. There are attempts to clarify the correct units for angular speed and the implications of using different units.

Discussion Status

The conversation is ongoing, with participants providing guidance on unit conversions and expressing confusion regarding the expected format for the final answer. There is a mix of interpretations about whether the final angular speed should be in radians per second or revolutions per second.

Contextual Notes

There is a noted ambiguity regarding the required units for the final answer, leading to further questions about the conversion process and the original poster's calculations.

riseofphoenix
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What is given:

Torque: τ = 34.5 N * m
Inertia: I = 0.130 kg * m2
Angular speed: ω = ?
Work done by a constant Torque: τΔθ = (1/2)Iωf2 [STRIKE]- (1/2)Iωi2[/STRIKE]
Angular displacement: Δθ = 17.1 rev/s = 107.442 rad/sτΔθ = (1/2)Iωf2
(34.5)(107.442) = (0.5)(0.130)ωf2
3706.765 = 0.065ωf2
57027.156 = ωf2
238.8 = ω

It's still wrong :(
 
Last edited:
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Δθ is 17.1 revolutions. You need to convert that to radians.
 
Make sure your angular displacement is in radians, not revolutions.
 
Change 17.1rev's to ... radians's.
 
3x should be enough :biggrin:
 
Doc Al said:
3x should be enough :biggrin:

Wait what? :(
 
grzz said:
Change 17.1rev's to ... radians's.

I just did and it's still wrong
 
riseofphoenix said:
I just did and it's still wrong
Show what you did.
 
If you show your work help may be given.
 
  • #10
Doc Al said:
Show what you did.

B]What is given:[/B]

Torque: τ = 34.5 N * m
Inertia: I = 0.130 kg * m2
Angular speed: ω = ?
Work done by a constant Torque: τΔθ = (1/2)Iωf2 [STRIKE]- (1/2)Iωi2[/STRIKE]
Angular displacement: Δθ = 17.1 rev/s
Conversion (17.1 x 2 x π) rad/s = 107.442

τΔθ = (1/2)Iωf2
(34.5)(107.442) = (0.5)(0.130)ωf2
3706.765 = 0.065ωf2
57027.156 = ωf2
238.8 = ω
 
  • #11
grzz said:
If you show your work help may be given.

But I just did o.O
 
  • #12
Looks like they want the speed in rev/s, not rads/sec.
 
  • #13
Doc Al said:
Looks like they want the speed in rev/s, not rads/sec.

Sooo...I don't convert angular displacement?
 
  • #14
riseofphoenix said:
Sooo...I don't convert angular displacement?
Convert your answer for ω from rad/s to rev/s.
 
  • #15
Doc Al said:
Convert your answer for ω from rad/s to rev/s.

τΔθ = (1/2)Iωf2
(34.5)(107.442) = (0.5)(0.130)ωf2
3706.765 = 0.065ωf2
57027.156 = ωf2
238.8 rad/s = ω

238.8/2π rev/s = ω
38 rev/s = ω

Awesome :o
Thanks!
 
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