Work done by gravity on a car rolling down a hill

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physicsmaster123
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I tried E =Fxcos0 but only ended up with 243kJ
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What values of ##F##, ##x##, and ##\theta## did you use and why?
 
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Hint: What is the textbook definition of ##\theta## in the formula you stated?
 
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physicsmaster123 said:
I tried E =Fxcos0 but only ended up with 243kJ
What distance in the diagram is ##50\cos(8°)##m?
 
Specific to this exercise, ##W=\Delta E_P## is a better fit than ##W=Fd\cos \theta##
 
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