Work done enclosing sphere with spherical shell - for tommorow

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ghosts_cloak
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Hi guys!
I have been working on this question all day and am getting no where :cry: I really can't get to grips with Electromagnetism, arghh!
The question is :http://www.zen96175.zen.co.uk/problem.GIF
I would NOT like anyone to post a solution as its assessed work but I would IMMENSELY appreciate some pointers on how to get started on this...
I have a few hours left to complete this, I hope somebody has a few pointers :!) :smile:
Thank you ,

~Gaz
 
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Hiya,
Well, that's the point really, I need a little push to get me started!
I am thinking it involves seeing how much work it takes to bring a hoop of charge from the spherical shell to the sphere, and then integrating over the whole shell. And then, integrate from r to a to make up the final large sphere is mentions? Pretty vague I know :cry:
Just looking for some pointers if anyone can!

Thank you!
~Gareth
 
ghosts_cloak said:
Hiya,
Well, that's the point really, I need a little push to get me started!
I am thinking it involves seeing how much work it takes to bring a hoop of charge from the spherical shell to the sphere, and then integrating over the whole shell. And then, integrate from r to a to make up the final large sphere is mentions? Pretty vague I know :cry:
Just looking for some pointers if anyone can!

Thank you!
~Gareth

I don't think you need to bring a hoop of charge, but you are on the right track. First find the work done in bringing the spherical shell from [itex]\infty[/itex] to [itex]r[/itex] and then integrate r from 0 to a.

To find the work done in bringing the shell, you will have to know the electric field due to sphere at the center, at a distance x and also the charge dq on the spherical shell (Hint: when the shell has finally enveloped the sphere, the charge dq is still going to be the same, so you can write dq in terms of r and dr). Then you can find the force on the spherical shell and hence the work done in bringing it to the sphere

I have not evaluated the double integral myself, but I think it should give you the answer.
 
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Phew, after a whole day on it, I think I have cracked it! This feeling is what makes physics and maths the greatest!

Thanks for your help,
~Gareth