Work Done on a Block on an Inclined Plane

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SUMMARY

The discussion focuses on calculating the work done on a block of mass 18 kg pushed up an inclined plane at an angle of 32° with a horizontal force of 150 N. The work done by the applied force (Fp) is determined using the equation W = Fpx * x, where Fpx is the component of the force parallel to the incline. The gravitational work (Wg) is calculated as Wg = mgsinθ * x, while the work done by the normal force (WN) is zero since there is no displacement in the direction of the normal force. The impact of friction is acknowledged, indicating that it affects the acceleration of the block but does not alter the fundamental work calculations.

PREREQUISITES
  • Understanding of Newton's laws of motion
  • Familiarity with work-energy principles
  • Knowledge of inclined plane mechanics
  • Basic proficiency in trigonometry
NEXT STEPS
  • Study the effects of friction on work and energy in mechanical systems
  • Learn about the work-energy theorem and its applications
  • Explore inclined plane problems involving different coefficients of friction
  • Investigate the relationship between kinetic energy and work done by non-conservative forces
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Students studying physics, particularly those focusing on mechanics, as well as educators looking for examples of work done on inclined planes with friction considerations.

gunjay
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Homework Statement


A block of mass m=18kg is pushed horizontally with a force of Fp=150N up an inclined plane of angle θ=32° and coefficient of friction of μ=0.10, a distance of x=5m. a) What is the work done by Fp. b) Work done by the gravitational force. c) Work done by the normal force.


Homework Equations


W = ∫Fdl
Force in the same direction as displacement.
or W = F*x

The Attempt at a Solution


My main question is how is work affected by friction?
This question is like a part 2 where the first one had no friction and this one does but i don't see how friction gets involved at all.

a) The Fp has 2 components, one that moves parallel to the inclined plane and the other perpendicular to the plane. so Fpx=Fpcosθ. So including friction do i do W = (Fpx-Ff)*x or just W=Fpx*x or ?

b) Wg=∫Fgdx = mgsinθ*x

c) WN=∫FNdx = 0 = there is no displacement in the direction of the normal force.
 
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a) You got it with your second equation there. It's irrelevant whether you are fighting against gravity, friction, or little green men pushing back in the opposite direction. Work is work.

b) and c) You got it. Friction only causes the block to accelerate slower.
 
I believe i found the answer.
There was a part d that i thought didn't apply but it did. d) asks for the velocity of the block after it moves those 5m. Using KE= net W i was able to find an answer using friction that also seems plausible.
 

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