Work done using time, velocity and mass?

AI Thread Summary
The discussion revolves around calculating the work done on a 1200kg vehicle as it decelerates from 90 km/h to 50 km/h over 8 seconds. The correct formula for work is established as W = 0.5 * m * v^2 - 0.5 * m * u^2, where m is mass, v is final velocity, and u is initial velocity. Participants clarify the need to convert velocities from km/h to m/s for accurate calculations. The final answer for work done is determined to be approximately -2.59 x 10^5 Joules, with some confusion initially regarding unit conversions. The discussion highlights the importance of using the correct formulas and units in physics problems.
TDizzl
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Homework Statement



The law of conservation of energy applies to the motion of vehicles. Find the work done on a 1200kg vehicle when it slows from 90kmh-1 to 50kmh-1 in 8.0 seconds.

Homework Equations



W=1/2mv^2 - 1/2mu^2

The Attempt at a Solution


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W=0.5*1200*50^2 - 0.5*1200*50^2
 
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If you assume a constant deceleration, you can use constant acceleration equations such as x = 1/2(vo + v)*t and v = vo + a*t. Work = Fd, where F is the force and d is the displacement. This can be expanded to W = m*a*d. Using the acceleration equations, you should be able to find all of your unknowns and plug them into the work equation.
 
TDizzl said:
W=0.5*1200*50^2 - 0.5*1200*50^2
Is that what you meant to post? What happened to the 90kmph?
cnstntcnfsn said:
If you assume a constant deceleration...
Why would TDizzl care what the rate of deceleration is?
 
Yes, my bad
Its W=0.5*1200*50^2 - 0.5*1200*90^2
 
cnstntcnfsn said:
Using the acceleration equations

The question is from a paper which does not require the use of constant acceleration equations. It would seem bizarre to use a formula that hasn't been introduced to us yet.
Also, the solution is written as -2.59*10^5 Joules in the paper.
 
TDizzl said:
Yes, my bad
Its W=0.5*1200*50^2 - 0.5*1200*90^2

You're not proposing to leave that as your answer, are you?
 
PeroK said:
You're not proposing to leave that as your answer, are you?
No, that was how I substituted the values in as an attempt to answer the question.
 
TDizzl said:
Yes, my bad
Its W=0.5*1200*50^2 - 0.5*1200*90^2
In what units?
 
haruspex said:
In what units?
m=1200kg
v=50kmh-1
u=90kmh-1
 
  • #10
TDizzl said:
m=1200kg
v=50kmh-1
u=90kmh-1
So what is it in Joules?
 
  • #11
haruspex said:
So what is it in Joules?
Yea its like -3360000J, that's what I got
 
  • #12
TDizzl said:
Yea its like -3360000J, that's what I got
No, the speeds you are given are in kmh-1, not ms-1.
 
  • #13
So how do I get the answer as -2.59×105?
 
  • #14
TDizzl said:
So how do I get the answer as -2.59×105?
How do you convert km/h to m/s?
 
  • #15
Alright -2.59×105 is the answer I got, the problem was that I was doing 502/3.6 instead of (50/3.6)2.
Thanks for the help, feeling extremely stupid. :mad:
 
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