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1. The problem statement, all variables and given/known data
a 2.1*10^3 kg car starts from rest at the top of a driveway that is sloped at an angle of 20 with the horizontal. An average friction force of 4.0*10^3 N impedes the car's motion so that the car's speed at the bottom of the driveway is 3.8m/s., What is the length of the driveway?


2. Relevant equations



3. The attempt at a solution

Ff=4000N
2100 Kg
X=20 degrees
Vf=3.8 m/s
Vi=0 m/s

Wnet=1/2MVf^2-1/2MVi^2
Wnet= 1/2*2000*3.8^2
Wnet= 15162 N

Wnet = FfdcosX
15162=4000cos20D
D=4.03m

but the book says 5.1m?
i cant figure out what i did wrong
thx for the help.
 

Doc Al

Mentor
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966
You forgot about gravity. Friction just slows the car; it's gravity which pulls it down the slope.

To find the net work you must consider all the forces: gravity and friction. (Don't forget that they act in different directions.)
 
i see so the force applied would be Fgravity*sin20 which would give me 7045.96 and i would subtract the Ff to get the total force. right?
 
Last edited:

Doc Al

Mentor
44,641
966
i see so the force applied would be Fgravity*sin20 which would give me 7045.96 and i would subtract the Ff to get the total force. right?
Right!
 
thxxx
 

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