World-building for fantasy story

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The discussion focuses on world-building for a fantasy setting in a binary star system, specifically a moon orbiting a gas giant. Key considerations include the need for shielding from radiation, the effects of tidal forces from the gas giant and other moons, and the resultant weather patterns influenced by the gas giant's proximity. The moon is likely to be tidally locked, resulting in long days and extreme temperature variations, potentially making it inhospitable. The stability of orbits in a binary system poses challenges for maintaining a habitable environment in the Goldilocks zone, suggesting that a more stable configuration might involve a planet closely orbiting one star with the second star at a greater distance. Overall, careful analysis of orbital mechanics and environmental factors is essential for creating a believable setting.
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I'm doing some world-building at the moment for a fantasy setting and would like some help, please. When it comes to physics etc, I'm like the kid who looks at the cool pictures of kung fu masters doing awesome kung fu stuff; less experienced than the student wielding a brand new white belt. Some guidance from you kung fu masters would be beneficial.

Here's the general concept:
1. The setting is located in a binary system with a sun slightly larger and brighter than our own, and one about half as such.
2. More precisely, the setting is a moon that orbits around a gas giant, which in turn orbits the two stars within the system's Goldilocks zone.
3. The gas giant is approximately the size of Jupiter, with 4-5 total moons.
4. The second moon is where everything within the setting takes place; although slightly smaller than Earth, it is more replete with heavy material, and thus of nearly equal gravity.

So here are my first set of questions:
1. What is necessary to include in this setting to ensure that earth-like civilizations could develop? For example, shielding from radiation, tidal forces from the gas giant, etc?
2. What kind of tidal forces would the moon experience from both the gas giant and the other surrounding moons? I'm assuming that a moon with sufficient distance from the gas giant wouldn't be trembling with volcanic activity.
3. What kind of weather effects would be occurring as a consequence of having a giant ball of gas hovering nearby? Would it be, all things considered equal, warmer/dryer/wetter than Earth?
4. Would reflection from the gas giant negate darkness in whatever regions of the moon were facing the gas giant, but not the suns?
5. How would light from the suns work? Would they appear as a large blob of light or separate points? Would they "rise" and "set" together? What about shadows cast by objects?
6. Would it make more sense to have the suns closer together and all of the satellites circling both or have one stationary and the other moving?
 
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Most of your questions require detailed knowledge of the system. A lot more details than we are currently given. Just that the gas giant is "in the Goldilocks zone" is not enough to tell us everything.

If you really want to know how the environment on this moon would be like, you will need the detailed orbits of the planet around the stars and the moon around the planet, as well as the orbits of the other moons. The main difficulty that I see here is finding stable orbits of a binary system where your planet will remain in the Goldilocks zone throughout its orbit. As you can imagine, figuring out the stable orbits for a binary system is far more difficult than for a single star. That's where I would start my analysis, if I had to have a binary system as the parent stars.
 
Seems to me, there's going to be quite a problem having a planet orbiting a binary system. It would have to be very distant from the two in order to be stable. But then how could it be in the Goldilocks Zone?

A more stable sitch is to have the planet closely orbit one of the stars, with the second star in a long period orbit outside the planetary system.
 
Thanks for the quick reply. Using Astrosynthesis v2.0, I get the following information:

Multistar system
Star 1: Mass 0.55, Radius 0.62, Luminosity 0.13 sols (all relative to our sun)
Star 2: Mass 1.57, Radius 1.44, Luminosity 4.8 sols (all relative to our sun)
Total of 12 primary satellites, with the gas giant in question the 5th planet

Gas Giant
Distance from Star 2 (assuming it orbits only one star) 125,695,818km
Eccentricity of orbit 0.18
Inclination (in degrees) 1.75
Ascending node (deg) 50.31
Periapsis Angle (deg) 34.78
Time past Periapsis (days) 7

Moon
Distance from gas giant 1,252,540km
Radius 6,504km
Gravity 1.02g
Retrograde orbit
Rotation 28hrs
Eccentricity of orbit 0.0185
Inclination (deg) 5.36
Ascending node (deg) 76.34
Periapsis angle (deg) 107.09
Time past Periapsis (days) 0
 
Star 2 is 4.8 times brighter than our sun, and the planet is about halfway between the distance from our Sun to Venus and the Earth...I'm guessing it's going to be quite hot over there.
 
Moons orbiting a jovian will always be tidally locked. (Unless the system is very young, or recently disrupted.) As a result, the "day" on these worlds will always be equal to the time they take to orbit their planet. The closest moon to Jupiter is Io. It's orbit is 1.769 days, and it gets hit with lots of nasty tidal forces causing volcanism.

So you are likely to get stuck with very long days on your moons.
 
Matterwave said:
Star 2 is 4.8 times brighter than our sun, and the planet is about halfway between the distance from our Sun to Venus and the Earth...I'm guessing it's going to be quite hot over there.

Yeah, I was thinking the same thing when looking at distance, although not quite at the same level of technical understanding. Pushing the distance further away would help cool things down.
 
Algr said:
Moons orbiting a jovian will always be tidally locked. (Unless the system is very young, or recently disrupted.) As a result, the "day" on these worlds will always be equal to the time they take to orbit their planet. The closest moon to Jupiter is Io. It's orbit is 1.769 days, and it gets hit with lots of nasty tidal forces causing volcanism.

So you are likely to get stuck with very long days on your moons.

For clarity, tidally locked means there is no rotation? The same side of the moon faces the gas giant the entire time? So essentially one side will always be day and the other night?
 
DaveC426913 said:
Seems to me, there's going to be quite a problem having a planet orbiting a binary system. It would have to be very distant from the two in order to be stable. But then how could it be in the Goldilocks Zone?

A more stable sitch is to have the planet closely orbit one of the stars, with the second star in a long period orbit outside the planetary system.

Does this address your concern in any way? http://www.astrobio.net/news-exclusive/two-suns-could-make-more-habitable-moons/
 
  • #10
UKDisasters said:
For clarity, tidally locked means there is no rotation? The same side of the moon faces the gas giant the entire time? So essentially one side will always be day and the other night?

The "one side will be day and the other night" would only apply if the central body was the star, and not the gas giant. Tidally locked to the gas giant means one face will always face the gas giant. In terms of day and night, how ever long the period of orbit around the gas giant is is the period of day and night.
 
  • #11
Matterwave said:
The "one side will be day and the other night" would only apply if the central body was the star, and not the gas giant. Tidally locked to the gas giant means one face will always face the gas giant. In terms of day and night, how ever long the period of orbit around the gas giant is is the period of day and night.

At the moon's distance, the software is telling me the orbit around the gas giant is approximately 10 local days. So this means it would take that many days to transition from day to night and back? So this could be sped up by moving the moon closer to the gas giant, which then introduces problems with increased volcanic activity etc. Is there another way to increase the speed of the day?
 
  • #12
UKDisasters said:
For clarity, tidally locked means there is no rotation? The same side of the moon faces the gas giant the entire time? So essentially one side will always be day and the other night?

Tidally locked means the rotation exactly matches the revolution. Earth's moon is tidally locked to the Earth, so the sun will rise and set every 28 days, but the Earth will always be in (almost) the same place in the lunar sky.

Edit: So this means it would take that many days to transition from day to night and back? So this could be sped up by moving the moon closer to the gas giant, which then introduces problems with increased volcanic activity etc.

That's right.
 
  • #13
UKDisasters said:
Yeah, I was thinking the same thing when looking at distance, although not quite at the same level of technical understanding. Pushing the distance further away would help cool things down.

5 times the flux means 5 times the heat input. Of course, without knowing the green-house effect, and albedo (reflectivity) of your planet, we can't really predict an average temperature.

But let's say there's no green house effect, and Albedo is 0. In-coming flux: ##F=\frac{L}{4\pi d}\approx 5*\text{solar~constant}\approx 7000W/m^2##. Total incoming heat (assuming Earth sized moon): ##U_{in}=F\times\pi r^2\approx9\times 10^{17} W##. The outgoing radiation is ##U_{out}=4\pi r^2\sigma T^4## We can solve for the equilibrium temperature: $$T_{eq}=\left(\frac{1}{4\sigma}F\right)^{1/4}\approx 150^\circ C$$ Which is pretty hot...above boiling anyways. One might object that this calculation did not take into consideration the albedo and green house effects (among a vast number of other effects), but as a comparison, doing this exact same calculation for Earth gets you 5 degrees Celsius (the green house effect keeps us about 10 degrees warmer on average). Of course you need an atmosphere to distribute the heating more evenly between the day and night sides. An atmosphere means green-house effect, which means more heating. With tidal locking taken into account, probably this planet will be scorching hot on the day side, and like an oven at night.

Probably this planet is not in the habitable zone of the parent star.
 
  • #14
Here we go. From Wikipedia:

In contrast, the outer natural satellites of the gas giants (irregular satellites) are too far away to have become locked. For example, Jupiter's natural satellite Himalia, Saturn's natural satellite Phoebe, and Neptune's natural satellite Nereid have rotation periods in the range of ten hours, while their orbital periods are hundreds of days.
 
  • #15
Algr said:
Here we go. From Wikipedia:

In contrast, the outer natural satellites of the gas giants (irregular satellites) are too far away to have become locked. For example, Jupiter's natural satellite Himalia, Saturn's natural satellite Phoebe, and Neptune's natural satellite Nereid have rotation periods in the range of ten hours, while their orbital periods are hundreds of days.

So the moon needs to be further out from the gas giant in order to remain free from tidal lock?

By the way, all of this is very helpful. Thank you everyone.
 
  • #16
Matterwave said:
5 times the flux means 5 times the heat input. Of course, without knowing the green-house effect, and albedo (reflectivity) of your planet, we can't really predict an average temperature.

But let's say there's no green house effect, and Albedo is 0. In-coming flux: ##F=\frac{L}{4\pi d}\approx 5*\text{solar~constant}\approx 7000W/m^2##. Total incoming heat (assuming Earth sized moon): ##U_{in}=F\times\pi r^2\approx9\times 10^{17} W##. The outgoing radiation is ##U_{out}=4\pi r^2\sigma T^4## We can solve for the equilibrium temperature: $$T_{eq}=\left(\frac{1}{4\sigma}F\right)^{1/4}\approx 150^\circ C$$ Which is pretty hot...above boiling anyways. One might object that this calculation did not take into consideration the albedo and green house effects (among a vast number of other effects), but as a comparison, doing this exact same calculation for Earth gets you 5 degrees Celsius (the green house effect keeps us about 10 degrees warmer on average). Of course you need an atmosphere to distribute the heating more evenly between the day and night sides. An atmosphere means green-house effect, which means more heating. With tidal locking taken into account, probably this planet will be scorching hot on the day side, and like an oven at night.

Probably this planet is not in the habitable zone of the parent star.

So if the gas giant is moved further out, it'll cool down the temperatures. Add some atmosphere and albedo to keep it from getting too chilly. Or is it albedo that decreases heat? I have a hard time remembering that one.
 
  • #17
UKDisasters said:
So if the gas giant is moved further out, it'll cool down the temperatures. Add some atmosphere and albedo to keep it from getting too chilly. Or is it albedo that decreases heat? I have a hard time remembering that one.

Albedo makes the planet reflective. In general, it cools the planet down. You'd have to move the planet out a ways. However, remember that you are in a binary system. Where's the other star? I'm guessing the other star is farther out? There might not be a stable orbit at all distances and configurations.
 
  • #18
I should probably also point out that with such a bright star, you are going to get a large amount of ultra violet rays...which might be damaging to cellular organisms. So you would probably need some kind of protection by e.g. having a thick atmosphere or having your civilization live under water or in rocks or something.
 
  • #19
I'm not married to the luminosity of the star, so it may be easier to just tone it down one or two magnitudes. As for the distances between the two stars, I'm not entirely sure. Based upon the article I referenced earlier, it would seem that having the two stars close and orbiting one another would be the most advantageous for allowing life to develop and flourish on a moon.

And to clarify why I'm aiming toward a binary system with a habitable moon is to break away from more "traditional" fantasy settings that, for good or bad, are more or less Earth with a different paint job. The question becomes what kind of cultures would develop where there are two suns in the sky and giant planet watching over you constantly. What would the effects be on agriculture and the economies. (Not to mention the enormous impact of magic on social structures, technology, meanings, etc.)
 
  • #20
The biggest problem, if you want to do "hard physics", like I stated is that you have to find the stable orbits for this Jovian planet. If you have a binary far away, they will both rise and set at the same time, so you'd just always see 2 Suns in the sky (or none). The distance you gave in post #4 means your planet is quite close to the larger star. If the other star is even closer still, it seems it would have to be making some very tiny orbits. I wouldn't know much more details than that though.
 
  • #21
Matterwave said:
The biggest problem, if you want to do "hard physics", like I stated is that you have to find the stable orbits for this Jovian planet. If you have a binary far away, they will both rise and set at the same time, so you'd just always see 2 Suns in the sky (or none). The distance you gave in post #4 means your planet is quite close to the larger star. If the other star is even closer still, it seems it would have to be making some very tiny orbits. I wouldn't know much more details than that though.

I can push the gas giant out, thus decreasing the temperature. Are there not instances of binary systems with planets that have stable orbits? I don't have the faintest idea how to calculate Jovian orbits, let alone any type of orbit. (Jovian means gas giant, is that correct?)

What if the moon was tidally locked but had no rotation?

Also, would proximity of sorts to the gas giant have any affect on the moon's temperature? What about reflected radiation from the gas giant? I'm assuming that the moon's atmosphere would absorb enough to keep it all at safe levels.

Edit:
Doing some research on orbits, this is what I pulled from wikireality:
Orbital stability
For a stable orbit the ratio between the moon's orbital period Ps around its primary and that of the primary around its star Pp must be < 1/9, e.g. if a planet takes 90 days to orbit its star, the maximum stable orbit for a moon of that planet is less than 10 days. Simulations suggest that a moon with an orbital period less than about 45 to 60 days will remain safely bound to a massive giant planet or brown dwarf that orbits 1AU from a Sun-like star.

Is that along the lines of what you are mentioning?
 
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  • #22
UKDisasters said:
I can push the gas giant out, thus decreasing the temperature. Are there not instances of binary systems with planets that have stable orbits? I don't have the faintest idea how to calculate Jovian orbits, let alone any type of orbit. (Jovian means gas giant, is that correct?)

What if the moon was tidally locked but had no rotation?

Also, would proximity of sorts to the gas giant have any affect on the moon's temperature? What about reflected radiation from the gas giant? I'm assuming that the moon's atmosphere would absorb enough to keep it all at safe levels.

Edit:
Doing some research on orbits, this is what I pulled from wikireality:
Orbital stability
For a stable orbit the ratio between the moon's orbital period Ps around its primary and that of the primary around its star Pp must be < 1/9, e.g. if a planet takes 90 days to orbit its star, the maximum stable orbit for a moon of that planet is less than 10 days. Simulations suggest that a moon with an orbital period less than about 45 to 60 days will remain safely bound to a massive giant planet or brown dwarf that orbits 1AU from a Sun-like star.

Is that along the lines of what you are mentioning?


That's one problem to deal with, but the other problem is that orbits around binary stars is hard to figure out because you have a restricted 3-body problem instead of the standard 2 body problem. Your planet is orbiting 2 stars which must, in fact, orbit each other. If you are far enough away from the center of mass of the 2 stars, you can treat the 2 stars as 1 plus perturbations, but in general this is a quite difficult problem to solve. You might consider trying to google "stable orbits around binary systems".
 
  • #23
UKDisasters said:
Here's the general concept:
1. The setting is located in a binary system with a sun slightly larger and brighter than our own, and one about half as such.
2. More precisely, the setting is a moon that orbits around a gas giant, which in turn orbits the two stars within the system's Goldilocks zone.
3. The gas giant is approximately the size of Jupiter, with 4-5 total moons.
4. The second moon is where everything within the setting takes place; although slightly smaller than Earth, it is more replete with heavy material, and thus of nearly equal gravity.

So here are my first set of questions:
1. What is necessary to include in this setting to ensure that earth-like civilizations could develop? For example, shielding from radiation, tidal forces from the gas giant, etc?
2. What kind of tidal forces would the moon experience from both the gas giant and the other surrounding moons? I'm assuming that a moon with sufficient distance from the gas giant wouldn't be trembling with volcanic activity.
Tidal forces from gas giant depend on eccentricity.
UKDisasters said:
3. What kind of weather effects would be occurring as a consequence of having a giant ball of gas hovering nearby? Would it be, all things considered equal, warmer/dryer/wetter than Earth?
Little effect. The solar warmth on Earth varies by 6 % due to Earth orbital eccentricity. This is not noticeable, and seasons are caused by tilt of Earth axis instead.
UKDisasters said:
4. Would reflection from the gas giant negate darkness in whatever regions of the moon were facing the gas giant, but not the suns?
Yes.
UKDisasters said:
5. How would light from the suns work? Would they appear as a large blob of light or separate points? Would they "rise" and "set" together? What about shadows cast by objects?
Your later specifications - 4,8 times solar brightness for the bigger and 0,13 for the smaller stars - suggests little effect on shadows when suns are high in sky. Though perhaps some.
But compare with Kepler-16, that actually exists.
Binary orbital period - 41 days
Binary distance - 0,22 AU
Planet´s orbital period - 229 days (so 5,6 times binary period)
Planet´s orbital distance - 0,705 AU.
So the binary distance is 0,32 times planet´s distance.
Compare Mercury.
Period 88 days (so 4,2 orbits per year)
Orbital distance average 0,387 AU, but with eccentricity varies between 0,307 and 0,467 AU.
So, looking from Kepler-16b, the orbit of 16B looks much like the perihelion of Mercury.

Would they rise and set together? Yes, like Mercury and Venus rise and set together with Sun.

But B is tremendously brighter than Mercury!

On Earth, Venus us something like 600 million times dimmer than Sun. Venus shines in evening and morning twilight brighter than any other star, but it is never bright enough to outshine the combined light of all other stars, or cast shadows.
Moon does outshine combined light of stars and cast shadows. Full Moon is 400 000 times dimmer than Sun. When Moon is near Sun, however, it is a narrow crescent and very much dimmer than when at full. Still, a large crescent Sun can easily be seen in broad daylight.
But a star like your B would shine plainly visible high in sky, and if it is above horizon when A is underneath (or even close) it would outshine the twilight.

Yes, they would sometimes merge into a blob. But such mutual occultation would last something in the region of a few hours. Although, with the dazzling disc of sun in the sky, it might not be particularly easy to notice, just like small phase partial solar eclipses are not easy to notice.
UKDisasters said:
6. Would it make more sense to have the suns closer together and all of the satellites circling both or have one stationary and the other moving?

More sense than what? What sense of "stationary"?
 
  • #24
2 more ideas:
-put the planet (with its habitable moon) in Lagrangian point http://en.wikipedia.org/wiki/Lagrangian_point
-make everything orbit the big star and put the small star as far as we have Neptun (like 30 AU)

If it is a moon with long day night cycle:
-make the atmosphere dense (water boils in higher temperature) and less big continents and more islands with sea around that would make those temperature jumps lower (or just make interior of continents a hell)
-adjust flora and fauna accordingly - think about hairy leaves and coniferous-like plants that survive such jumps more or less fine, while animals hide into holes
-if the atmosphere is much denser then any flying creatures have much easier life

If you have a star much bigger than the Sun you must take into account that it has shorter life and a billion years earlier was much dimmer. (was the planet a while ago hot enough?)
 
  • #25
Czcibor said:
2 more ideas:
-put the planet (with its habitable moon) in Lagrangian point http://en.wikipedia.org/wiki/Lagrangian_point
http://en.wikipedia.org/wiki/Lagrangian_point
http://en.wikipedia.org/wiki/Lagrangian_point
Binary stars don´t have them.
http://en.wikipedia.org/wiki/Lagrangian_point
Czcibor said:
-make everything orbit the big star and put the small star as far as we have Neptun (like 30 AU)
Compare Alpha Centauri. Small stat 35,6 AU from big star at apoapse. And big star does qualify under "slightly brighter than Sun".
 
  • #26
snorkack said:
Binary stars don´t have them.

Technically they have them. When I thought about it this idea would be infeasible for this story purpose from different reasons.

wiki:
"The triangular points (L4 and L5) are stable equilibria, provided that the ratio of M1/M2is greater than 24.96."

So it could theoretically be a dim red dwarf (less than 0,1 solar mass) and too short (for 2,5 solar mass around1 bln years) lived massive star.
 
  • #27
For example of what kinds of binary stars are common, key parametres of nearest binaries
Toliman AB: masses 1,10/0,91 solar; eccentricity 0,52; distance 11,2/35,6 AU; period 79,9 Earth years
Sirius AB: 2,02/0,98; 0,59; 8/32 AU; 50,1 y
61 Cygni AB: 0,70/0,63; 0,49; 44/124 AU; 678 y
Procyon AB: 1,42/0,60; 0,41; 8,9/21 AU; 40,8 y
Keid BC: 0,50/0,20; 0,41; 21/49 AU; 252 y
70 Ophiuchi AB: 0,90/0,70; 0,50; 11,4/38 AU; 88,3 y
Achird AB: 0,97/0,57; 0,50; 36/106 AU; 480 y
36 Ophiuchi AB: 0,85/0,85; 0,922; 7/169 AU; 569 y.
 
  • #28
DaveC426913 said:
Seems to me, there's going to be quite a problem having a planet orbiting a binary system.
Turns out, I could not have been more wrong.

Not only is it possible, it exists!
Check out Kepler-16b

In fact, here's NASA's travel poster for it.
http://planetquest.jpl.nasa.gov/image/183

http://planetquest.jpl.nasa.gov/system/avm_image_sqls/images/183/medium/Kepler-16b_20x-30.png?1418688766
 
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  • #29
Thats awesome. where do I book tickets?
 
  • #30
as for the habitability. since you are designing the solar system from the ground up, why not just make the central star exceedingly luminous? Put the gas giant and its moon very far away so it circles both stars but make the central star and intensely bright star so that your homeworld (homemoon?) will still receive adequate warmth even if its 30 AU away (or however far is needed for a stable orbit) this of course wouldn't bode well for the first 4 planets in your system so hopefully you don't need any rival civilizations in your home system ;)
 
  • #31
DHF said:
as for the habitability. since you are designing the solar system from the ground up, why not just make the central star exceedingly luminous? Put the gas giant and its moon very far away so it circles both stars but make the central star and intensely bright star so that your homeworld (homemoon?) will still receive adequate warmth even if its 30 AU away (or however far is needed for a stable orbit) this of course wouldn't bode well for the first 4 planets in your system so hopefully you don't need any rival civilizations in your home system ;)
You know that the brighter the star, the shorter its life? So bright enough star at 30 AU would not not provide habitable zone for long enough period.
(If you don't belief I may do the math and show it)
 
  • #32
no I believe you, It was a simple oversight. you are right of course. a star bright enough to shine the reaches of a pluto like orbit would have a lifespan of only a few million years. not long enough for life to evolve.
 
  • #33
So the trick is how bright can he make the pair of stars in order to keep their lifespan in the Billions of years range while at the same time providing enough luminosity to warm the homeworld at an orbital distance that would keep it stable.
 
  • #34
Try to review again - what are the constraints on the orbital distance needed for stability?
 
  • #35
Weather will be fairly extreme. With two suns and a gas giant nearby, there will be some complex and intense seasonal patterns. If the moon goes into the shadow of the gas giant, it will get cold and dark. This might replace the concept of night, but it could last much longer. If the rotation is tidally locked, then the side facing the gas giant will be in shadow most of the time. But with two suns, you'll have periods illuminated by one sun but not the other, and periods of illumination by both or neither. It will be much more extreme than Earth.
 
  • #36
Khashishi said:
Weather will be fairly extreme.
Why?
Khashishi said:
With two suns and a gas giant nearby, there will be some complex and intense seasonal patterns.
Complex, sure. Intense, why?
Khashishi said:
If the moon goes into the shadow of the gas giant, it will get cold and dark. This might replace the concept of night, but it could last much longer.
No, it couldn´t. Night is necessarily half the orbit. Eclipse necessarily less than half. Can be much less than that. Moon has a night of half a month (360 hours), but total lunar eclipse is under three hours.
Khashishi said:
If the rotation is tidally locked, then the side facing the gas giant will be in shadow most of the time.
Literally, yes. Half the time is night, i. e. shadow of ground, and a small fraction of the rest is eclipse/shadow of the gas giant, so a slight majority of time is in shado of something and not in direct sunlight.
Khashishi said:
But with two suns, you'll have periods illuminated by one sun but not the other, and periods of illumination by both or neither.
And illumination by the gas giant. So you have 3 illumination sources.
Khashishi said:
It will be much more extreme than Earth.
No. More complex, but why more extreme?
 
  • #37
snorkack said:
Why?

Complex, sure. Intense, why?

No. More complex, but why more extreme?
Two suns should make the climate a bit complex.
But one risk getting the climate extreme if the moon orbit is not very short.

No, it couldn´t. Night is necessarily half the orbit. Eclipse necessarily less than half. Can be much less than that. Moon has a night of half a month (360 hours), but total lunar eclipse is under three hours.

Literally, yes. Half the time is night, i. e. shadow of ground, and a small fraction of the rest is eclipse/shadow of the gas giant, so a slight majority of time is in shado of something and not in direct sunlight.
One may play here with plains. In perfect case you may have eclipses each time. In more typical case - not often.

It's possible to have an eclipse each midday or a two eclipse seasons, pending on angle

And illumination by the gas giant. So you have 3 illumination sources.
For heat purposes one may ignore one source. Just for story reasons there would be light enough to see something during night because of reflected light.
 
  • #38
Czcibor said:
Two suns should make the climate a bit complex.
But one risk getting the climate extreme if the moon orbit is not very short.
True. Long orbit means long nights.
Czcibor said:
One may play here with plains. In perfect case you may have eclipses each time. In more typical case - not often.

It's possible to have an eclipse each midday or a two eclipse seasons, pending on angle
Since the moon´s axis of rotation is necessarily aligned with its orbital plane, it ties into the moon having or not having season. If the moon has darkness every day, it likely does not have seasons either. If the moon has seasons then there are necessarily two eclipse seasons, namely spring and autumn.
Czcibor said:
For heat purposes one may ignore one source. Just for story reasons there would be light enough to see something during night because of reflected light.

Oh, sure.
Earth has Moon.
Full Moon is an appreciable source of light. A night lit by full Moon is hundreds of times brighter than a moonless night lit by stars alone. Man sees not only something in moonlight, but also possesses some colour vision. The sky is noticeably brighter in full moonlight... though its colour (objectively blue) is not visible.
Earth´s rotation is not locked to Moon, so Moon rises and sets. It´s not visible through all nights.
Moon is locked to Earth. For an observer on the near side of Moon, Earth is always in sky, by day and throughout night.
And since Earth is reflecting sunlight, the phases of Earth are fixed to visibility of Sun. At midnight (new Moon), Earth is necessarily full. At sunrise (half Moon) Earth is necessarily half. Earth does wane to crescent... but only by day. Nights on Moon near side are always illuminated by full or at least gibbous Earth.

Now, Earth is bigger than Moon. Almost 4 times by length. Roughly 14 times by area.

And Moon is black. Earth is about 3 times more reflective than even full Moon.
In total, full Earth is estimated at 43 times brighter than full Moon.

Also, Moon fades dramatically when not full. Half moon shows half the illuminated surface of full Moon - yet only 1/9 of the light!

Earth does not fade so badly. Half Earth should be slightly less than half the brightness of full Earth (who knows exactly how much?) but still much brighter than full Moon.

In terms of lux, the illumination of full Moon is about 0,27 lux. Illumination of full Earth should then be about 12 lux.

For comparison, the suggested targets for street lighting seem to be 5...10 lux.

When you build a town in the middle of near side of Moon, you can save money by omitting streetlights. Earth will provide that level of lighting all night. You would still need lamps inside the homes and on working tables, though.
 
  • #39
snorkack said:
Since the moon´s axis of rotation is necessarily aligned with its orbital plane, it ties into the moon having or not having season. If the moon has darkness every day, it likely does not have seasons either. If the moon has seasons then there are necessarily two eclipse seasons, namely spring and autumn.
Yes. Assuming of course that orbit of the gas giant is not seriously eccentric. In such case there would be another source of seasons. (I'm not sure how to calculate that)

I wonder that whether frequent and long eclipses in midday would have some impact on one of hemispheres.

When I think about it if the planet is supposed to be Jupiter mass, then it should be bigger. Why? Jupiter contracts because of loosing heat, while it this case the planet would get more heat from its stars so should contract slower. (or reach an equilibrium?)

Oh, sure.
Earth has Moon.
Full Moon is an appreciable source of light. A night lit by full Moon is hundreds of times brighter than a moonless night lit by stars alone. Man sees not only something in moonlight, but also possesses some colour vision. The sky is noticeably brighter in full moonlight... though its colour (objectively blue) is not visible.
Earth´s rotation is not locked to Moon, so Moon rises and sets. It´s not visible through all nights.
Moon is locked to Earth. For an observer on the near side of Moon, Earth is always in sky, by day and throughout night.
And since Earth is reflecting sunlight, the phases of Earth are fixed to visibility of Sun. At midnight (new Moon), Earth is necessarily full. At sunrise (half Moon) Earth is necessarily half. Earth does wane to crescent... but only by day. Nights on Moon near side are always illuminated by full or at least gibbous Earth.

Now, Earth is bigger than Moon. Almost 4 times by length. Roughly 14 times by area.

And Moon is black. Earth is about 3 times more reflective than even full Moon.
In total, full Earth is estimated at 43 times brighter than full Moon.

Also, Moon fades dramatically when not full. Half moon shows half the illuminated surface of full Moon - yet only 1/9 of the light!

Earth does not fade so badly. Half Earth should be slightly less than half the brightness of full Earth (who knows exactly how much?) but still much brighter than full Moon.

In terms of lux, the illumination of full Moon is about 0,27 lux. Illumination of full Earth should then be about 12 lux.

For comparison, the suggested targets for street lighting seem to be 5...10 lux.

When you build a town in the middle of near side of Moon, you can save money by omitting streetlights. Earth will provide that level of lighting all night. You would still need lamps inside the homes and on working tables, though.
Such moon would get light from gas giant. (Jupiter - 11 times Earth diameter) So local civilization after inventing fire to survive long nights would need much more time to invent candles? :D
 
  • #40
Czcibor said:
Such moon would get light from gas giant. (Jupiter - 11 times Earth diameter) So local civilization after inventing fire to survive long nights would need much more time to invent candles? :D
Man depends on fire even in broad daylight, because man is an omnivore whose guts rely on good quality cooked food.

If they have cold nights or winters and need fire to warm themselves, they have a reason to invent lamps anyway. Lamps are easier to invent than clear window glass.
 
  • #41
I've been wondering why so many wants to go into other planets when we still have so much to do to improve Earth and our own part of the universe. why not a story about building Earth in your vision, then we have nine more planets in our solar system to your world-building imagination, plus countless moons, etc?

if you want it to be a game, perhaps try Simcountry, http://www.simcountry.com/cgi-bin/cgip?ad&miSite=promo231142
I've played this game for awhile now, there are still lots of things I think could be done better, but the owner don't ever listen to anyone.

personally, I think the Earth is the perfect place to start a world-building alternative version :)
 
  • #42
UKDisasters said:
Thanks for the quick reply. Using Astrosynthesis v2.0, I get the following information:

Multistar system
Star 1: Mass 0.55, Radius 0.62, Luminosity 0.13 sols (all relative to our sun)
Star 2: Mass 1.57, Radius 1.44, Luminosity 4.8 sols (all relative to our sun)
Total of 12 primary satellites, with the gas giant in question the 5th planet

Gas Giant
Distance from Star 2 (assuming it orbits only one star) 125,695,818km
Eccentricity of orbit 0.18
Inclination (in degrees) 1.75
Ascending node (deg) 50.31
Periapsis Angle (deg) 34.78
Time past Periapsis (days) 7

Moon
Distance from gas giant 1,252,540km
Radius 6,504km
Gravity 1.02g
Retrograde orbit
Rotation 28hrs
Eccentricity of orbit 0.0185
Inclination (deg) 5.36
Ascending node (deg) 76.34
Periapsis angle (deg) 107.09
Time past Periapsis (days) 0
Using your values I was able to calculate a few things that may interest you.

Star 1 would have an effective surface temperature of 4,406°K, which would make the star a spectral Type K star. Not factoring in albedo or radiative forcing, the habitable zone range for Star 1 would be between 0.200 and 0.375 AU.

Star 2 would have an effective surface temperature of 7,127°K, which would make the star a spectral Type F star. The habitable zone for Star 2 would be between 1.22 and 2.28 AU.

You mentioned in your original post that you wanted both stars to be in a close binary orbit, but you did not specify the distance between the two stars. Since both stars orbit their common center of mass (barycenter), they would have to be in a fairly close orbit in order to keep the habitable zone relatively stable.

The distance you placed the gas giant (125,695,818 km) is only 0.84 AU from Star 2. That is far too close, and would give the gas giant (and any moons in orbit around the gas giant) a mean surface temperature closer to Mercury or Venus than Earth. The gas giant should have a semi-major axis closer to ~261,792,290 km (1.75 AU) from Star 2. At 1.75 AU from Star 2, a black body object would have a mean surface temperature of ~50°C. While that is well within the liquid water range, that is too hot for complex life to exist. Ideally, the mean surface temperature should be half that or slightly less, somewhere between 20°C and 25°C (based upon Earth's life forms). You can accomplish this by: 1) moving the gas giant further away from the barycenter of the two stars; or 2) significantly increasing the albedo of the moon; or 3) a combination of the two - moving the gas giant further away and increasing the albedo of the moon.

My calculations did not factor in albedo or radiative forcing. Depending on the chemical composition and density of the atmosphere on the moon, the greenhouse gases in the atmosphere may also add a significant amount of warming. On Earth, the amount of sunlight reaching the planet is 1,367 W/m2 with 1,050 W/m2 of direct sunlight reaching the surface of the planet, and another 70 W/m2 of indirect sunlight also reaching the surface for a total of 1,120 W/m2. Radiative forcing due to the greenhouse gases on Earth accounts for an additional ~72 W/m2.

Obtaining a retrograde orbit of the moon would be extremely difficult to accomplish. There is only one moon that has achieved hydrostatic equilibrium with a retrograde orbit in our solar system - Triton. Nobody is sure how Triton obtained its retrograde orbit around Neptune. Triton is spectroscopically similar to Pluto, and it is therefore thought that Triton may have been a captured Kuiper Belt object. A naturally forming moon, made of the same accretion disk that formed the gas giant, should not have a retrograde orbit.

In order to determine the orbital characteristics of the moon, you will need to include the mass of the gas giant. The moon's distance of 1,252,540 km from the gas giant would most likely mean that the moon is tidally locked to the gas giant (similar to the moon Triton), but without knowing the mass of the gas giant that is impossible to determine. Keep in mind that the gas giant mass must be less than ~14 Jupiter masses, otherwise it will start fusing deuterium and be considered a brown dwarf star and no longer a planet.
 
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