Would a wire's magnetic field increase the net-B field?

AI Thread Summary
When a wire carrying current is placed in an external magnetic field, it generates its own magnetic field that interacts with the external field, resulting in the Lorentz force. The wire's magnetic field can either oppose or support the external field, but for practical purposes, magnetic fields do not directly interact; their effects can be summed to determine the total field at a point. The confusion often arises from differing interpretations of how the force on the wire is understood, with some referencing Faraday's perspective of field line interactions while others focus on the external field's action on the wire. Clear distinctions between these approaches are necessary for effective learning, as mixing them can lead to misconceptions. Ultimately, the external magnetic field's influence on the wire is the primary concern in applications like motors.
PhiowPhi
Messages
203
Reaction score
8
From the following diagram:

MagF_4.gif


When a wire is placed in a magnetic field ##B##, and current starts to flow within that wire. It creates it's own magnetic field(##B_w##). Will ##B_w## interact with the external field ##B##? If it does, is the result of the interaction the Lorentz force?

Also from the direction of current the wire's magnetic field could oppose or support the external field, will that decrease/increase the total magnetic field, causing ##\Delta## (##\phi##) and will induced -##\epsilon## to oppose the change?

Because in applications related to the Lorentz force I study(motors) the induced ##\epsilon## I am aware of, are from self-inductance of the wire, or the motion of the wire which causes the change in area. Not sure of anything else...
 
Physics news on Phys.org
For all practical purposes, magnetic fields do not interact with each other. You can just add different contributions to find the total field at a point. They can influence other magnetic dipoles but that is a different type of interaction. The magnetic field of the wire is irrelevant if you want to study the effect of the outside magnetic field on the wire - as long as your wire does not influence the magnetic dipoles in the magnet.
 
  • Like
Likes PhiowPhi
I assumed that the field of the current-carrying wire would somehow increase/decrease the external magnetic field. Thanks for clearing out that misconception @mfb.
 
I think that any confusion arises from there being two ways of 'understanding' the force on a current-carrying wire…

The 'Faraday picture' considers the RESULTANT of the wire's magnetic field and the external magnetic field. The resultant field lines are bunched on one side of the conductor and spaced out on the other, forming a swirly pattern. So far, so uncontroversial. But Faraday regarded the stretched and bunched-together field lines on one side of the wire as acting like a catapult and pushing 'sideways' on the current-carrying wire (as compared to the more spaced-out lines on the other side of the wire).

The modern approach is that the force arises by the action of the EXTERNAL field on the wire.

Confusion is caused when textbooks and teachers don't make a clear enough distinction between the approaches, so that the student gets a mixture of the two. One could argue that there's not a very strong case for teaching the catapult approach at all.
 
Thread 'Motional EMF in Faraday disc, co-rotating magnet axial mean flux'
So here is the motional EMF formula. Now I understand the standard Faraday paradox that an axis symmetric field source (like a speaker motor ring magnet) has a magnetic field that is frame invariant under rotation around axis of symmetry. The field is static whether you rotate the magnet or not. So far so good. What puzzles me is this , there is a term average magnetic flux or "azimuthal mean" , this term describes the average magnetic field through the area swept by the rotating Faraday...
Back
Top