Would someone me with some basic algebra?

[Krazie]

How would I simplify this equation? (3a^3)^-3(9a^-1)^-2
When I put those carrots in that means the next number is an exponent. Is there any easier way to write exponents?

 

[Krazie]

How would I simplify this one: (2a^-1)^-2(2a^-1)^4

 

[Krazie]

Would the simplified expression of the second equation be 4/a ?

 

[Muzza]

Carrot That's "caret", btw

Anyway, "distribute" some of the exponents. For example, $$(2a^{-1})^{-2} = 2^{-2} \cdot a^{(-1)(-2)} = \frac{1}{2^2} \cdot a^2 = a^2/4$$. Then do the same for the other paranthesis, multiply them together, etc.

The last one is almost 4/a, it's 4/a^2...

 

[HallsofIvy]

As far as "(2a^-1)^-2(2a^-1)⁴" is concerned, there is a general formula: a^xa^y= a^x+y.


(Edit: replaced x*y with x+y!)

 

[loseyourname]

When I put those carrots in that means the next number is an exponent. Is there any easier way to write exponents?

You can use LaTeX typesetting. Refer to this thread: https://www.physicsforums.com/showthread.php?t=8997

Also, you can click on the expressions that Muzza typed out to see how he did it.

 

[hello3719]

As far as "(2a^-1)^-2(2a^-1)⁴" is concerned, there is a general formula: a^xa^y= a^x*y.

you mean a^xa^y= a^x+y

 

[Krazie]

ah nice hello. I thought that I was the only one that caught that. That would be sad. Thanks guys, this really helps, sorry if I bore you all with these simple problems, but i have to start somewhere.

 

[Zurtex]

As far as "(2a^-1)^-2(2a^-1)⁴" is concerned, there is a general formula: a^xa^y= a^x*y.

Do you perhaps mean (a^x)^y = a^x*y?

 

[HallsofIvy]

Yes, I just corrected it!