X-t plot of underdamped motion

  • Thread starter Thread starter AlonsoMcLaren
  • Start date Start date
  • Tags Tags
    Motion Plot
AI Thread Summary
The discussion centers on the x-t plot of underdamped motion, highlighting the intersection of two curves: one representing e^{-at} and the other e^{-at}cos(bt). At their intersection, the red curve has a slope of zero while the blue curve has a nonzero slope, raising questions about potential additional intersection points. The accuracy of the plot is questioned due to visible "kinks" in the blue curve, suggesting it may not be drawn precisely. It is clarified that mathematically, the two curves should not intersect at multiple points, as they reach their maximum and minimum values at different times. The conversation emphasizes the importance of accurate plotting in understanding the behavior of underdamped motion.
AlonsoMcLaren
Messages
89
Reaction score
2
Here is the x-t plot of underdamped motion:

http://www.google.com/imgres?q=unde...2&tbnw=151&start=0&ndsp=20&ved=1t:429,r:2,s:0

At the intersection of the red curve and the blue curve, the red curve has a slope of 0 but the blue curve has a nonzero slope.

Therefore, does it mean that these two curves actually intersect at some other points very close to the intersections already show in the plot?
 
Physics news on Phys.org
Don't try to read too much into the plot. It's not very accurately drawn. You can see some "kinks" in the top blue curve at about t= 0.2 and t= 0.4 which shouldn't be there.

Most likely it's a plot of e^{-at} and e^{-at}\cos(bt) (you can guess the values of a and b for yourself).

EDIT: first comment was wrong!

When \cos(bt) = 1, the slope of both curves is -a e^{-at} so the two curves touch at one point.

But the curves in your link are probably drawn by fitting a "smooth curve" through a set of points, and so they will not necessarily have the correct tangents and the two curves look as if they intersect twice.
 
Last edited:
But mathematically there shouldn't be any reason that the equation exp(-at)=exp(-at)cos(bt) have 2 solutions at each peak.
 
Or it might be the case that the red curve does not have a zero slope at the intersection. (Because exp(-at)cos(bt) and cos(bt) reach max/min at different t)
 
Sorry, my first comments in post #2 were wrong - now fixed.
 
The rope is tied into the person (the load of 200 pounds) and the rope goes up from the person to a fixed pulley and back down to his hands. He hauls the rope to suspend himself in the air. What is the mechanical advantage of the system? The person will indeed only have to lift half of his body weight (roughly 100 pounds) because he now lessened the load by that same amount. This APPEARS to be a 2:1 because he can hold himself with half the force, but my question is: is that mechanical...
Some physics textbook writer told me that Newton's first law applies only on bodies that feel no interactions at all. He said that if a body is on rest or moves in constant velocity, there is no external force acting on it. But I have heard another form of the law that says the net force acting on a body must be zero. This means there is interactions involved after all. So which one is correct?
Thread 'Beam on an inclined plane'
Hello! I have a question regarding a beam on an inclined plane. I was considering a beam resting on two supports attached to an inclined plane. I was almost sure that the lower support must be more loaded. My imagination about this problem is shown in the picture below. Here is how I wrote the condition of equilibrium forces: $$ \begin{cases} F_{g\parallel}=F_{t1}+F_{t2}, \\ F_{g\perp}=F_{r1}+F_{r2} \end{cases}. $$ On the other hand...
Back
Top