Xcel Energy's Comanche 3 Power Plant in Pueblo, CO

AI Thread Summary
The Comanche 3 power plant in Pueblo, CO, is designed to generate 750 MW using supercritical boiler technology, achieving a thermal efficiency of 42%. It utilizes Powder River Basin coal with a heating value of 8,500 BTU/lbm. A calculation error occurred in determining the annual coal consumption; the correct approach requires dividing by the efficiency rather than multiplying. The initial calculation incorrectly suggested an annual coal burn of 2.86 billion kg. The accurate method focuses on the energy input needed rather than the output produced.
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Homework Statement


The Comanche 3 power plant currently being constructed in Pueblo, CO, by Xcel Energy will
produce 750 MW of power. This plant uses supercritical boiler technology which will boost the
thermal efficiency to 42%. The plant uses Powder River Basin coal from Gillette, WY, that has a
heating value of 8,500 BTU/lbm. Find the amount of coal burned in this plant each year.


Homework Equations


n=\frac{what you get}{what you paid for}

The Attempt at a Solution


So I made the conversion from 8500 BTU/lbm to 19.7710 MJ/kg (megajouls)
I did 750E6 times .42 which is 315E6 MW.
I did \frac{315E6 MW}{19.7710 MJ/kg} which is 15.932 kg/s
I times that by 3600*24*365 to get g in a year and get 5.024E8 kg.
The answer is 2.86x109 kg, what did I do wrong?
 
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You need to divide by 0.42 not multiply.
You want to know how many MJ of coal your are paying for, not what you get out of it!
 
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