If xy + 9e^y = 9e, find the value of y'' at the point where x = 0.
The Attempt at a Solution
Okay so first I found the first derivative using implicit differentiation and I got:
then, I found the second derivative to be:
the website won't let me enter y' so I substituted it into the second derivative and then set x=0 and I got:
I'm not quite sure if I'm doing this right so I'd like a second opinion. I only have one attempt left and I don't want to get it wrong!