Yet Another Question on the Complex Square Root Function .... Palka, Example 1.5, Chapter III

• MHB
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I am reading Bruce P. Palka's book: An Introduction to Complex Function Theory ...

I am focused on Chapter III: Analytic Functions, Section 1.2 Differentiation Rules ...

I have yet another question regarding Example 1.5, Section 1.2, Chapter III ...

Example 1.5, Section 1.2, Chapter III, reads as follows:

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About half way through the above example from Palka we read the following:

" ... ... Since $$\displaystyle \mid 1/ \sqrt{z} \mid \ = 1/ \sqrt{ \mid z \mid } \to \infty$$ as $$\displaystyle z \to 0$$ ... ... "

Can someone please explain exactly how/why $$\displaystyle \ \mid 1/ \sqrt{z} \mid \ = 1/ \sqrt{ \mid z \mid }$$ ...

Help will be appreciated ...

Peter

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• Palka - 1 - Example 1.5, Section III - PART 1 ... .png
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• Palka - 2 - Example 1.5, Section III - PART 2 ... .png
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