You are traveling on a straight road with constant velocity

[Tonia]

Homework Statement

At the beginning of a 10 sec. interval your position is measured to be 80 ft East with respect to a reference object. At the end of the 10 sec. interval your position is measured to be 965 ft East with respect to the same reference object.
Determine your velocity at t = 3.45 sec.
Determine your velocity at t = 6.9 sec.
Calculate the area under the entire V-t graph. What does this area respresent?

Homework Equations

m(slope) = v = change in x divided by change in t = Xf - Xo/tf - to =
965ft - 80ft/10 sec- 0sec = 885ft/10sec = 88.5met/sec. East

The Attempt at a Solution

Area = Vot = 10 sec times 88.5 met/sec = 885 meters This represents the displacement of the car.
The velocity of the car at t = 3.45 sec and at t = 6.9 sec is 88.5 met/sec.

 

[phinds]

I assume your question is whether or not you got the right answers, yes? It's always a good idea to state your question, even if it seems obvious to you.

It looks good to me.

 

[RyanH42]

885ft/10sec = 88.5met/sec. East

I did not understand this ft-meter transformation

 

[Tonia]

Yes, I just wanted to make sure I did it right. Thanks.

 

[Tonia]

It was a typo I made.

 

[phinds]

I did not understand this ft-meter transformation

Good catch. Probably just a typo but I breezed right past it.

 

[RyanH42]

I have a question.Why we ignore acceleration of car.Maybe car is accelerating ?

 

[Tonia]

I have a question.Why we ignore acceleration of car.Maybe car is accelerating ?

The car is not accelerating, it's going at a constant velocity of 88.5 met/sec.

 

[vela]

Read the thread title.

 

[RyanH42]

Read the thread title.

Ooppsss Sorry