Zin of a circuit with independent sources

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SUMMARY

The discussion focuses on calculating the input impedance (Zin) for a Low Noise Amplifier (LNA) circuit with independent sources. The user initially attempts to derive Zin using the formula Zin = V1/Iin but struggles with the dependency on V1. The correct approach involves determining Zin by turning off all independent sources, leading to the expression Zin = s(Lg + Ls) + 1/(gg + sCgs), where 's' is replaced with 2πfi. This method allows for the separation of real and imaginary components of the impedance.

PREREQUISITES
  • Understanding of input impedance in electrical circuits
  • Familiarity with Low Noise Amplifiers (LNA)
  • Knowledge of complex numbers and frequency domain analysis
  • Proficiency in applying Kirchhoff's laws in circuit analysis
NEXT STEPS
  • Study the calculation of input impedance using circuit analysis techniques
  • Learn about the implications of independent sources in circuit design
  • Explore the use of complex impedance in AC circuit analysis
  • Investigate the role of conductance and capacitance in LNA performance
USEFUL FOR

Electrical engineers, circuit designers, and students focusing on amplifier design and impedance calculations will benefit from this discussion.

anhnha
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Hi,
This is not a homework question. I need to calculate input impedance for a LNA and this is part of it.
How do you calculate input impedance, Zin, for the circuit below?
I tried by applying an input voltage, V1, and calculate Iin.
Input impedance will be V1/Iin. However, the expression still contains V1 and I can't figure out how to
make it independent on V1.

There is another method that I am not sure.
Input impedance will be equal to the impedance as all independent sources are turned off.
This means that Zin in the picture will be equal to s(Lg + Ls) + 1/(gg + sCgs)

gg is a conductance.

attachment.php?attachmentid=65427&stc=1&d=1389234912.jpg
 

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Your equation (s(Lg + Ls) + 1/(gg + sCgs)) is the impedance. Someone please confirm, but all you need to do is replace 's' with 2*pi*f*i where i is the imaginary number sqrt(-1) and f is the frequency in hertz. Then solve the resulting complex equation into real and imaginary parts.
 
I don't know what the application could be but, assuming the two sources (V1 I1) are coherent, the input impedance (V12/i(in)) seen by V1 will depend upon the phase of the current I1. Have I read the circuit diagram right?

You could solve this using Kirchoff (as always) but there may be an easier way.
 

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