Implicit differentiation

by aanandpatel
Tags: implicit diff., stationary point
aanandpatel is offline
Feb20-12, 03:55 AM
P: 16
1. The problem statement, all variables and given/known data

Find the coordinates of the stationary points on the curve:
x^3 + (3x^2)(y) -2y^3=16

2. Relevant equations
Stationary points occur when the first derivative of y with respect to x is equal to zero

3. The attempt at a solution
I implicitly differentiated the equation and got
dy/dx = (x^2 + 2xy) / (2y^2 - x^2)

I know I have to make this equal to zero but then I'm not sure how to find the x and y coordinates of the stationary point.

Help would be greatly appreciated :)
Phys.Org News Partner Science news on
Going nuts? Turkey looks to pistachios to heat new eco-city
Space-tested fluid flow concept advances infectious disease diagnoses
SpaceX launches supplies to space station (Update)
ehild is offline
Feb20-12, 04:36 AM
HW Helper
P: 9,818
Hi aanandpatel,

Find y in terms of x from the condition dy/dx=0. Substitute back into the original equation.

HallsofIvy is offline
Feb20-12, 06:43 AM
Sci Advisor
PF Gold
P: 38,882
You have two equations,
[tex]x^3 + (3x^2)(y) -2y^3=16[/tex]
[tex](x^2 + 2xy) / (2y^2 - x^2)= 0[/tex]
to solve for x and y. The second equation can easily be solved for y in terms of x since a fraction is equal to 0 if and only if the numerator is 0.

aanandpatel is offline
Feb21-12, 04:37 AM
P: 16

Implicit differentiation

Thanks guys - helped a lot! :)

Register to reply

Related Discussions
Implicit differentiation help Calculus & Beyond Homework 3
Implicit differentiation Calculus & Beyond Homework 2
Solve by Implicit Differentiation or Partial Differentiation? Calculus & Beyond Homework 12
implicit differentiation Calculus & Beyond Homework 2
Implicit differentiation Calculus & Beyond Homework 3