- #1
KFSKSS
- 14
- 0
Member has been warned not to delete the template.
Hello. My problem is as follows: Suppose x^4+y^2+y-3=0. a) Compute dy/dx by implicit differentiation. b) What is dy/dx when x=1 and y=1? c) Solve for y in terms of x (by the quadratic formula) and compute dy/dx directly. Compare with your answer in part a).
I solved a) and b). a)=-4x^3/2y+1, and b)=-4/3. I'm stuck at c). This is what I've been doing: Using the quadratic formula to solve for y in x^4+y^2+y-3=0 gives y=(-1±√-4x^4+13)/2. Then applying the chain rule in the result of y gives -(4x^3)/√-4x^4+13. But it must give the same as a)= -4x^3/2y+1. Where am I failing at? How can I solve it?
Thank you for your time.
I solved a) and b). a)=-4x^3/2y+1, and b)=-4/3. I'm stuck at c). This is what I've been doing: Using the quadratic formula to solve for y in x^4+y^2+y-3=0 gives y=(-1±√-4x^4+13)/2. Then applying the chain rule in the result of y gives -(4x^3)/√-4x^4+13. But it must give the same as a)= -4x^3/2y+1. Where am I failing at? How can I solve it?
Thank you for your time.