Copper wire and shove it into the positive terminal

AI Thread Summary
Inserting a copper wire into the hot terminal of an electrical outlet and grounding it can create a short circuit, leading to a significant current flow until a circuit breaker trips or the wire fuses. This action poses serious safety risks, including the potential for electric shock or fire. Electrical outlets do not have positive terminals; they consist of hot, neutral, and ground connections. Such dangerous practices are strongly discouraged due to the high risk of injury or property damage. Engaging in this behavior could have fatal consequences.
MotoPayton
Messages
96
Reaction score
0
If I were to take a copper wire and shove it into the positive terminal of an electrical outlet and then stick the other side of the copper wire into the earth, will current flow??
 
Physics news on Phys.org
Of course .. and lots for a brief time till the copper wired fused or the house circuit breaker tripped

Why would you want to do such a dopey thing ?
You are setting yourself to be a darwin Award contender

if you don't do and don't even consider such actions you will " Live Long And Prosper"
cheers
Dave
 
Electrical outlets don't have positive terminals, only hot, neutral and ground. If you meant the hot terminal, yes, current will flow, including through you if you aren't protected.
 
MotoPayton said:
If I were to take a copper wire and shove it into the positive terminal of an electrical outlet and then stick the other side of the copper wire into the earth, will current flow??
It's called a short circut (or line-to-ground fault). Hopefully a breaker would trip somewhere, otherwise one risks starting a fire if the circuit overheats. That is a dangerous activity that we discourage.
 
Thread 'Gauss' law seems to imply instantaneous electric field'
Imagine a charged sphere at the origin connected through an open switch to a vertical grounded wire. We wish to find an expression for the horizontal component of the electric field at a distance ##\mathbf{r}## from the sphere as it discharges. By using the Lorenz gauge condition: $$\nabla \cdot \mathbf{A} + \frac{1}{c^2}\frac{\partial \phi}{\partial t}=0\tag{1}$$ we find the following retarded solutions to the Maxwell equations If we assume that...
I passed a motorcycle on the highway going the opposite direction. I know I was doing 125/km/h. I estimated that the frequency of his motor dropped by an entire octave, so that's a doubling of the wavelength. My intuition is telling me that's extremely unlikely. I can't actually calculate how fast he was going with just that information, can I? It seems to me, I have to know the absolute frequency of one of those tones, either shifted up or down or unshifted, yes? I tried to mimic the...
Back
Top