- #1
AeroFunk
- 17
- 0
Let R be the region bounded by the graphs of x+y=1, x+y=2, 2x-3y=2, and 2x-3y+5. Use the change of variables:
[tex]
x=1/5(3u+v)[/tex]
[tex]y=1/5(2u-v)[/tex]
to evaluate the integral:
[tex]
\iint(2x-3y)\,dA
[/tex]
I found the jachobian to be -1/5
and the limits of integration to be
1<=u<=2
2<=v<=5
so i set up the integral like this:
[tex]
\frac{-1}{5}\int_{2}^{5}\int_{2}^{1} vdv[/tex]
and I get -21/5 which doesn't seem right(a negitive number??),what am I doing wrong?
[tex]
x=1/5(3u+v)[/tex]
[tex]y=1/5(2u-v)[/tex]
to evaluate the integral:
[tex]
\iint(2x-3y)\,dA
[/tex]
I found the jachobian to be -1/5
and the limits of integration to be
1<=u<=2
2<=v<=5
so i set up the integral like this:
[tex]
\frac{-1}{5}\int_{2}^{5}\int_{2}^{1} vdv[/tex]
and I get -21/5 which doesn't seem right(a negitive number??),what am I doing wrong?