- #1
frankkk
- 2
- 0
I am trying to solve a homework problem. I need some help to get going in the right direction if possible. My equation I am starting with is:
Vc(t) = 5(1-e^(-t/T))
and I have to end up with these two equations:
If T > 1/10f then for a 5 V square wave with a 50% duty cycle, the capacitor voltage is given by
Vc(t) = 5 - (5 / 1+e^(-1/2*f * T)) * e^(-t/T)
and
Vc(t) = (5 / 1+e^(-1/2*f * T)) * e^(-t/T)
Thanks!
Vc(t) = 5(1-e^(-t/T))
and I have to end up with these two equations:
If T > 1/10f then for a 5 V square wave with a 50% duty cycle, the capacitor voltage is given by
Vc(t) = 5 - (5 / 1+e^(-1/2*f * T)) * e^(-t/T)
and
Vc(t) = (5 / 1+e^(-1/2*f * T)) * e^(-t/T)
Thanks!
Last edited: