- #1
indigojoker
- 246
- 0
Show the matrix representation of [tex] S_z [/tex] using the eigenkets of [tex]S_y[/tex] as base vectors.
I'm not quite sure on the entire process but here's what i think:
We get the transformation matrix though:
[tex]U = \sum_k |b^{(k)} \rangle \langle a^{(k)} | [/tex]
where |b> is the eigenket for S_y and <a| is the eigenket for S_z
this will give me a change of basis operator that i can operate on the S_z operator to get it into the S_y basis.
would this be the correct though process?
I'm not quite sure on the entire process but here's what i think:
We get the transformation matrix though:
[tex]U = \sum_k |b^{(k)} \rangle \langle a^{(k)} | [/tex]
where |b> is the eigenket for S_y and <a| is the eigenket for S_z
this will give me a change of basis operator that i can operate on the S_z operator to get it into the S_y basis.
would this be the correct though process?