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offbeatjumi
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** sorry. this would be Newtons 2nd law of motion. oops.
Hockey puck with mass 0.160kg at rest at x=0 and t=0 on horizontal frictionless surface. hockey player applies force of 0.250 N until t = 2.00s. ... ... if the same force is applied again at t = 5.00 s what is the position and speed of the puck at t = 7.00s?
x(final) = x(initial)+v(initial)t+(1/2)a(t^2)
v(final) = v(initial)+at
at t = 2 seconds, the puck is at x = 3.125m and the velocity is 3.125m/s. the acceleration (from F = ma) is 1.5625 m/s^2.
how do I incorportate reapplying the force? i imagine since the surface is frictionless and the acceleration is constant that the puck keeps increasing in velocity right?
Homework Statement
Hockey puck with mass 0.160kg at rest at x=0 and t=0 on horizontal frictionless surface. hockey player applies force of 0.250 N until t = 2.00s. ... ... if the same force is applied again at t = 5.00 s what is the position and speed of the puck at t = 7.00s?
Homework Equations
x(final) = x(initial)+v(initial)t+(1/2)a(t^2)
v(final) = v(initial)+at
The Attempt at a Solution
at t = 2 seconds, the puck is at x = 3.125m and the velocity is 3.125m/s. the acceleration (from F = ma) is 1.5625 m/s^2.
how do I incorportate reapplying the force? i imagine since the surface is frictionless and the acceleration is constant that the puck keeps increasing in velocity right?
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